Sort and count files according to first letter of file name

» java » Sort and count files according to first letter of file name

By : user2957382

Date : November 24 2020, 01:01 AM

wish of those help a classic way to do that is make a Map with each letter a key and the count for that letter the value

code :

List<String> names = new ArrayList<>();
Map<Character,Integer> map = new HashMap<>();
for (String name : names)
  {
  char firstLetter = name.charAt(0);
  if( map.containsKey(firstLetter) )
    map.put(firstLetter, map.get(firstLetter)+1 );
  else
    map.put(firstLetter, 1);
  }

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uppercase Letter count, lowercase letter count, blank count, and lower to upper conversion- C

By : Charles L

Date : March 29 2020, 07:55 AM

hop of those help? I'm somewhat new to the language (C), but what i am trying to do is pretty simple imo. i'm sure im just neglecting something or running into some logical errors.

code :

if ((iochar=' ')||(iochar='\t')||(iochar='\n'))

if ((iochar==' ')||(iochar=='\t')||(iochar=='\n'))

Bash - sort by first letter of file name

By : Ginny Ghezzo

Date : March 29 2020, 07:55 AM

fixed the issue. Will look into that further I'm not 100% sure it will work, but give sort -V a try.
EDIT: As jordanm notes, this is apparantly a newer GNU extension.

How to use file name to sort and count files stored in a .mat file?

By : Bogdan Siderek

Date : March 29 2020, 07:55 AM

this will help If you mean that you want to get a list of the variables in a *.mat file that start with d1, d2, etc. You could use who and matfile to get a list of all variables. who accepts a regular expression which you can create specific to the variables you want to see.

code :

matobj = matfile('filename.mat');

d1vars = who(matobj, '-regexp', '^d1h');
nD1 = numel(d1vars);

for k = 1:3
    vars{k} = who(matobj, '-regexp', ['^d', num2str(k), 'h']);

    % And get the number
    nVars(k) = numel(vars{k});
end

data = load('filename.mat');
variables = fieldnames(data);

isd1 = variables(~cellfun(@isempty, regexp(variables, '^d1h')));
nD1 = numel(isd1);

Batch file to count files matching first 6 characters in file name and output file group and its count

By : Cristian Crane

Date : March 29 2020, 07:55 AM

will be helpful for those in need I would like to have a batch file to count all file names with common prefix and output the file group and its count. I have these files in a directory: , Here is a batch code for this task.

code :

@echo off
setlocal EnableExtensions
for %%I in ("*.zip") do call :CountFile "%%~nI"
for /F "tokens=2,3 delims=#=" %%I in ('set Group# 2^>nul') do echo %%I: %%J
endlocal
goto :EOF

:CountFile
set "FileName=%~1"
set "FileGroup=%FileName:~0,6%"
if "Group#%FileGroup%" == "" (
    set "Group#%FileGroup%=1"
) else (
    set /A Group#%FileGroup%+=1
)
goto :EOF

How do I count the letter N in an output file, which is a list of strings written to a txt file?

By : user2680352

Date : March 29 2020, 07:55 AM

it helps some times Use file.readlines() to iterate over the file line by line as a string. You can then simply use the count() method which counts the occurrence of a term in a string:

code :

def ncount(filename):
    count = 0
    with open(filename, 'r') as myfile:
        for line in myfile.readlines():
            count += line.count('N')
    return count
count = ncount("somefile.txt")
print(count)