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onEnter and onExit are not called when state is left/activated in angularjs ui router


onEnter and onExit are not called when state is left/activated in angularjs ui router

By : Celine
Date : November 22 2020, 03:03 PM
I hope this helps . Okay, I got it now. The first problem is that, if you are using nested views then you can't use onEnter & onExit callbacks there (at view level). You can only use them at state level configuration.
For reference documentation: https://github.com/angular-ui/ui-router/wiki/Multiple-Named-Views#views-override-states-template-properties
code :
.state('projects', {
    url: '/projects',
    views: {
      'menu@""': {
        template: 'Start your projects!'
      },
      'content@': {
        templateUrl: "projects.html",
        controller: 'ProjectsController'
      }
    }
  })
  .state('projects.create', {
    url: '/create',
    views: {
      'outer@': {
        templateUrl: 'projects.create.html',
        controller: 'ProjectWizardController'
      }
    },
    onEnter: function(){
       alert('hello onEnter');
    },
    onExit: function(){
        alert('hello onExit');
    }
  })


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cocos2d onEnter, onExit

cocos2d onEnter, onExit


By : Abhishek Jaiswal
Date : March 29 2020, 07:55 AM
wish of those help yeah, you are right. onExit is called when you remove node from it's parent, or when it's parent is removed from the stage/other parent.
Define the onEnter and onExit callbacks in another file with Angular UI Router

Define the onEnter and onExit callbacks in another file with Angular UI Router


By : Dara
Date : March 29 2020, 07:55 AM
To fix the issue you can do You can do this, but it without knowing more this is a code smell. You are mixing logic between controllers and states, but they should be separate.
Anyway, here's how you can do this:
code :
.controller('layersCtrl', function($state) {
  $state.get('map.layers').onEnter = blah;
  $state.get('map.layers').onExit = blahblah;
});
ui-router onEnter() not being called from $state.go() within Ionic app

ui-router onEnter() not being called from $state.go() within Ionic app


By : user3126389
Date : March 29 2020, 07:55 AM
I hope this helps you . Try moving the onEnter from within the view object up a level to the state object, I've just ran across this same problem and it seemed to work OK for me.
code :
    .state('tab.queries', {
        url: '/queries',
        views: {
            'tab-queries': {
                templateUrl: 'templates/tab-queries.html',
                controller: 'QueryCtrl'
            }
        },
        onEnter: function() {
            activate();
        }
    })
ui-router navigate to another state onEnter

ui-router navigate to another state onEnter


By : Naveed Hussain
Date : March 29 2020, 07:55 AM
Does that help charlietfl for the information, use resolve to process redirect looks good! Here's how I end up doing:
code :
var redirect = (returnState: string) => {
        return ['$q', '$timeout', '$state', 'dataModel', ($q, $timeout, $state, dataModel) => {
                var deferred = $q.defer();
                $timeout(() => {
                    if (dataModel.informationB === "") {
                        $state.go('wizardB.input', { rs: returnState });
                        deferred.reject();
                    } else {
                        // everything is fine, proceed
                        deferred.resolve();
                    }
                });

                return deferred.promise;
            }
        ];
    }
    resolve: {
            redirect: redirect("wizardA.input")
        }
onEnter/onExit method in React Native Component (react-native-router-flux)

onEnter/onExit method in React Native Component (react-native-router-flux)


By : S.Star
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Please check latest react-native-router-flux:beta.27, now you can define onEnter, onExit methods as your react component methods.
code :
class Home extends Component {
  static onEnter() {
    console.log('On Focus Enter')
  };
  static onExit() {
    console.log('On Focus Exit')
  }
}
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