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Using typedefs appropriately to avoid "typedef contamination"


Using typedefs appropriately to avoid "typedef contamination"

By : user2956850
Date : November 22 2020, 03:03 PM
I wish this help you You can limit related typedef's in namespaces. You can put the typedef's being used in just 1 class into that class. If a typedef is used in just few files, add the typedef in .cpp file.
code :


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having "typedef void FuncCharPtr" in one class how to feed function that uses that typedef with non static fun

having "typedef void FuncCharPtr" in one class how to feed function that uses that typedef with non static fun


By : Kocijan Ŧilip
Date : March 29 2020, 07:55 AM
this will help So I have a class like: , renderCastedData is a nonstatic member function. Its type is
code :
void (simpleRendererGraphElement::*)(char*, int)
template <typename Function>
void Add(Function f)
struct RenderCastedDataFunctor
{
    simpleRendererGraphElement* obj_;

    RenderCastedDataFunctor(simpleRendererGraphElement* obj)
        : obj_(obj) { }

    void operator()(char* castedChar, int castedCharLength)
    {
        obj_->renderCastedData(castedChar, castedCharLength);
    }
};
charGenerator->Add(RenderCastedDataFunctor(this));
Why can't we typedef an (unnamed) structure twice at file scope, but we can typedef "int" twice without error?

Why can't we typedef an (unnamed) structure twice at file scope, but we can typedef "int" twice without error?


By : Erik
Date : March 29 2020, 07:55 AM
will be helpful for those in need The following code compiles and runs fine: , The thing is that when you do:
code :
typedef struct
{

} Somestruct;
typedef struct Somestruct
{

} Somestruct;
How can I make a shared_ptr from an opaque pointer typedef? (or: how can I "unwrap" typedef?)

How can I make a shared_ptr from an opaque pointer typedef? (or: how can I "unwrap" typedef?)


By : Павел Труфанов
Date : March 29 2020, 07:55 AM
it should still fix some issue If you have an opaque pointer typedef, is there a way to dynamically refer to the pointed-to type, say, for use in templates? For instance, say you have something like this: , In C++11:
code :
#include <type_traits>

typedef std::shared_ptr< std::remove_pointer< FooPtr >::type > theSharedPtr;
template<class T> struct remove_pointer;
template<class T> struct remove_pointer<T*> { typedef T type; };
Avoid "unused typedef" warnings when wrapping with swig

Avoid "unused typedef" warnings when wrapping with swig


By : salik shastikar
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , if you want just to avoid warnings you can add -Wno-unused-local-typedef option
Numpy array value "contamination"

Numpy array value "contamination"


By : R.E.
Date : March 29 2020, 07:55 AM
it fixes the issue That's basically dilation operation in Image-processing domain. So, you can use Scipy's binary dilation -
code :
from scipy.ndimage import binary_dilation
out = binary_dilation(arr, structure=np.ones((3,3))).astype(int)
In [21]: arr
Out[21]: 
array([[0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0],
       [0, 0, 0, 1, 0, 0],
       [0, 0, 0, 0, 1, 0],
       [0, 0, 1, 0, 0, 0],
       [0, 0, 0, 0, 0, 0]])

In [22]: binary_dilation(arr, structure=np.ones((3,3))).astype(int)
Out[22]: 
array([[0, 0, 0, 0, 0, 0],
       [0, 0, 1, 1, 1, 0],
       [0, 0, 1, 1, 1, 1],
       [0, 1, 1, 1, 1, 1],
       [0, 1, 1, 1, 1, 1],
       [0, 1, 1, 1, 0, 0]])
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