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Order in order without using events


Order in order without using events

By : Moudhafer
Date : November 22 2020, 03:03 PM
I wish this help you Note that you can do this in a single query by using the WHERE as an ORDER itself; it will filter to the top all the ones where they are online and continue with the ones that are offline:
code :
SELECT * FROM users ORDER BY ('.time().' - c_last_act < 30) DESC, clan_rank DESC


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Query to order time events showing first future events and after show current events

Query to order time events showing first future events and after show current events


By : Khagendra Gautam
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have a table where i store events and it has 2 fields for dates. One for the start date (start_date) of the event and other for the end date (end_date). Some events dont have end_date defined or have end_date='1970-01-01'.
code :
SELECT *,
       DATEDIFF(start_time, CURDATE()) AS diff
FROM   events
WHERE  start_time >= CURDATE()
        OR ( start_time <= CURDATE()
             AND end_time >= CURDATE() )
ORDER  BY CASE
            WHEN diff > 0 THEN 0
            ELSE 1
          end,
          diff ASC;
Websphere Commerce Maximum Order Quantity Per Order Change to All Order history and pending

Websphere Commerce Maximum Order Quantity Per Order Change to All Order history and pending


By : pasquinade
Date : March 29 2020, 07:55 AM
may help you . We might need to create a new CommandTask and then append it to all existing flows.
OR
Why it is impossible to construct Binary Tree with Pre-Order, Post Order and Level Order traversals given?

Why it is impossible to construct Binary Tree with Pre-Order, Post Order and Level Order traversals given?


By : paidipalli anusha
Date : March 29 2020, 07:55 AM
it helps some times We can't build a tree without the in-order traversal. Why? Let's say you are given the pre-order and post-order traversals only.A simple example is shown below.
Consider two different trees,
code :
root=a;  
root->left=b;  
root->left->right=c;  
root=a;  
root->right=b;  
root->right->left=c;  
pre-order - a b c  
post-order - c b a  
SQL Access Order By Time (same time stamp) changes order of events based on name

SQL Access Order By Time (same time stamp) changes order of events based on name


By : ynsingh
Date : March 29 2020, 07:55 AM
hope this fix your issue I have an issue when sorting by time. I have a DB (using access DB) where some entries have exact same time (even seconds). When I sort the events by time, the table sorts the records by time first, then organizes them based on the first letter of the next column. , In Access, you can use Switch for this:
code :
'Select * From Events Where RunNo = ' + RunNo + ' ORDER By Time, Switch([Expination] = "Installing", 0, [Expination] = "Doing Something", 1, [Expination] = "Ready for use", 2)'
Query returning individuals most recent order, date of the order, number of products in the order and the total amount

Query returning individuals most recent order, date of the order, number of products in the order and the total amount


By : ric0
Date : March 29 2020, 07:55 AM
this will help It is always good practice to start from assumed dim tables such as product.This Query should help. It is better to aggregate quantity and amount to get results at aggregate level
code :
SELECT FirstName
    ,LastName
    ,max(o.orderdate) Orderdate
    ,Sum(Quantity) Quantity
    ,Sum(TotalAmount) TotalAmount
FROM Product p
INNER JOIN Orderitem oi
    ON Oi.product_id = p.id
INNER JOIN
ORDER o
    ON o.id = oi.order_id
INNER JOIN Customer c
    ON c.id = o.Customer_id
GROUP BY FirstName
    ,LastName
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