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How to find pattern matching and save to array with preg_match


How to find pattern matching and save to array with preg_match

By : user2956779
Date : November 22 2020, 03:03 PM
will help you I want to search url in string and save them into an array. , Use preg_match instead of preg_replace
code :
preg_match(
"/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i",
 $input, $matches);

print_r($matches[0]);


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Use preg_match() to find start/stop positions of a substring matching a pattern

Use preg_match() to find start/stop positions of a substring matching a pattern


By : user2068242
Date : March 29 2020, 07:55 AM
To fix this issue i'm not sure, but maybe you could use preg_split for that like this:
code :
$mysubtext = preg_split("/\d\|\d\w0:/", $mytext);

$mysubtext = preg_split("/\d\w\w\d+:\s-\s:/", $mysubtext[1]);

$mysubtext = $mysubtext[0];
preg_match matching pattern with asterisk (*) in it

preg_match matching pattern with asterisk (*) in it


By : Fritz
Date : March 29 2020, 07:55 AM
With these it helps To use literal asterisks you have to escape them with backslashes. To match the literal te**ed you would use an expression like this:
code :
preg_match('/te\*\*ed/i', 'tested', $matches); // no match (te**ed != tested)
preg_match('/te..ed/is', 'tested', $matches); // match
preg_match('/te[a-z]{2}ed/i', 'tested', $matches); // match
Preg_match PHP -- pattern matching

Preg_match PHP -- pattern matching


By : Cristian Nunes
Date : March 29 2020, 07:55 AM
I wish did fix the issue. well if your pattern is: SOMETHING + (YEAR) then your regex should be like this:
code :
 #^(.+)\((\d{4})\)$#
 # -> pattern delimiter
 ^ -> beginning of string
 (.+) -> any character "." once or more "+"
 \( -> escape parenthesis character
 \d{4} -> four digits
 \) -> escape parenthesis character
 $ -> end of string
Preg_match/Preg_replace in php for matching pattern and replacing it in php

Preg_match/Preg_replace in php for matching pattern and replacing it in php


By : Stefan
Date : March 29 2020, 07:55 AM
To fix the issue you can do I want to replace value in string with XXX , You can use this:
code :
$sql = 'insert into employees values(\'shrenik\', 555, NULL)';
$pattern = '~(?:\binsert into [^(]*\(|\G(?<!^),(?:\s*+NULL,)*)\s*+\K(\')?(?(1)[^\']*\'|(?!NULL\b)[^\s,)]*)~i';

$sql = preg_replace($pattern, '$1XXX$1', $sql);
~                           # pattern delimiter
(?:                         # non capturing group: where the pattern is allowed to start
    \binsert into [^(]*\(   # after "insert to" until the opening parenthesis
  |                         # OR
    \G(?<!^),               # after a precedent match if there is a comma
    (?:\s*+NULL,)*          # skip NULL values
)                         
\s*+                        # zero or more spaces
\K                          # reset all that was matched before from match result
(')?                        # optional capture group 1 with single quote 
(?(1)                       # IF capture group 1 exists:
    [^']*'                  # THEN matches all characters except ' followed by a literal '
  |                         # ELSE
    (?!NULL\b)[^\s,)]*      # matches all characters except spaces, comma, ) and the last NULL value
)                           # ENDIF
~i                          # closing pattern delimiter, case-insensitive
PHP preg_match not matching with an expression to pattern

PHP preg_match not matching with an expression to pattern


By : Etilepratice
Date : March 29 2020, 07:55 AM
it helps some times I have this php code , You're missing the closing parentheses for your if statement.
code :
if (preg_match('/BUT[a-zA-Z0-9]+TN/', $id))
                                          ^
$id = 'BUTEqHLHxJSRr9DJZSMTN';
preg_match('/BUT[a-zA-Z0-9]+TN/', $id, $match);
echo $match[0]; //=> "BUTEqHLHxJSRr9DJZSMTN"
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