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Xor bits in python


Xor bits in python

By : albertiko89
Date : November 22 2020, 10:56 AM
this will help First you need to zip your strings then use ord (in python 2) and ^ for each of characters :
code :
>>> s1 = b'abc'
>>> s2 = b'efg'
>>> ''.join(chr(ord(i)^ord(j)) for i,j in zip(s1,s2))
'\x04\x04\x04'
>>> ''.join(chr(i^j) for i,j in zip(s1,s2))
'\x04\x04\x04'
example :

>>> s1[0]
97
>>> s1[0:1]
b'a'
>>> import binascii 
>>> s=''.join(chr(i^j) for i,j in zip(s1,s2))
>>> s4=binascii.a2b_qp(s)
>>> ''.join(chr(i^j) for i,j in zip(s1,s4))
'efg'


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how to change system's COM Port settings( Bits,Data bits,Parity,Stop bits and flow control) by code in wpf?

how to change system's COM Port settings( Bits,Data bits,Parity,Stop bits and flow control) by code in wpf?


By : vipin tp
Date : March 29 2020, 07:55 AM
I wish this help you Those settings are stored in the registry at
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Ports
code :
            Microsoft.Win32.RegistryKey myKey = 
                Microsoft.Win32.Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows NT\\CurrentVersion\\Ports", true);
            string settings = myKey.GetValue("COM3:");
            Microsoft.Win32.RegistryKey myKey = 
                Microsoft.Win32.Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows NT\\CurrentVersion\\Ports", true);
            myKey.SetValue("COM3:", "9600,n,8,1");
python keep 60 right most bits out of 64 bits - type error

python keep 60 right most bits out of 64 bits - type error


By : Alex B.
Date : March 29 2020, 07:55 AM
this will help If I understand you correctly, you want to keep the 60 least significant bits, right? By rightshifting you would keep the 60 most significant bits.
code :
...6....'....5....'....4....'....3....'....2....'....1....'....0
DDDDKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK   Input
0000KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK   Output
num &= 0x0FFFFFFFFFFFFFFF
Given two unsigned char variables, assign the lowest 4 bits of A to be highest 4 bits of B, and the highest 4 bits of A

Given two unsigned char variables, assign the lowest 4 bits of A to be highest 4 bits of B, and the highest 4 bits of A


By : cyk858
Date : March 29 2020, 07:55 AM
help you fix your problem Follow these steps:
extract the 4 low order bits of a with a & 0x0F shift them left by 4 with the << operator extract the 4 high order bits of a with a & 0xF0 shift these right by 4 to bring them to the low order position with >> combine these results with |. add some parentheses to ensure correct precedence
How to interpret hex to unsigned long int (20-bits integer, 12-bits fraction, modulo 20-bits)

How to interpret hex to unsigned long int (20-bits integer, 12-bits fraction, modulo 20-bits)


By : user2996682
Date : March 29 2020, 07:55 AM
Hope this helps The 12-bits can represent 2**12 different numbers. It could represent the integers from 0 to 2**12 - 1 (i.e. 4095). If we were to take the decimal string representation of that integer and directly convert it to the fractional part of a second, then we would only be able to represent fractional seconds from 0 to 0.4096. That doesn't seem right.
To spread the fractional parts evenly between 0 and 1 we would want to divide by 4096:
code :
import numpy as np
datasample = np.array(['b1491fda 00001017 00040a88 00000000 0a 02 00c24d18 0076dd10 fd13fe3c 0032d8ce 0222c71a 01f0f0fa',
                       'b1492010 00001018 00040a88 00000000 0a 02 00c249aa 0076dbee fd148e86 0032dc34 02235336 01f0f3c8',
                       'b1492047 00001019 00040a88 00000000 0a 02 00c2463c 0076dacc fd151ed0 0032df9a 0223df52 01f0f696',
                       'b149207d 0000101a 00040a88 00000000 0a 02 00c248d0 0076da0a fd13fff4 003265b8 02239a24 01f0f3e0',
                       'b14920b4 0000101b 00040a88 00000000 0a 02 00c248d0 0076da0a fd13fff4 003265b8 02239a24 01f0f3e0',
                       'b14920eb 0000101c 00040a88 00000000 0a 02 00c1eed0 0076a812 fd148d00 0032b896 022396fe 01f0b4ac'],
                      dtype='|S98')
print(np.array([int(row[:8],16)  for row in datasample]) / 2**12)
[726161.99072266 726162.00390625 726162.01733398 726162.03051758 726162.04394531 726162.05737305]
result = (np.array([int(row[:8],16)  for row in datasample]) / 2**12)
print(np.diff(result))
# [0.01318359 0.01342773 0.01318359 0.01342773 0.01342773]
datasample10 = np.array(['b1a2f9ea 000012ea 00040a88 00000000 0a 02 00c230d4 007671a6 fd1c2538 002b512e 021b9f7c 01f14944',
           'b1a39a8e 000015db 00040a88 00000000 0a 02 00c1d26c 0076b032 fd1c3554 002d51b2 021bd5a0 01f0cd92'],
          dtype='|S98')

result = (np.array([int(row[:8],16)  for row in datasample10]) / 2**12)
print(np.diff(result))
# [10.04003906]
result = (np.array([int(row[:8],16)  for row in datasample]) % 2**20 / 2**12) 
print(result)
# [145.99072266 146.00390625 146.01733398 146.03051758 146.04394531 146.05737305]
import datetime as DT
print((DT.datetime.now() - DT.datetime(2010,1,1)).total_seconds())
# 301151491.085063
Write a program to clear bits 7 and 6, set bits 5 and 4, and toggle bits, 3, 2, 1, and 0?

Write a program to clear bits 7 and 6, set bits 5 and 4, and toggle bits, 3, 2, 1, and 0?


By : markmark
Date : March 29 2020, 07:55 AM
it helps some times I don't know 68k assembly but why such a long program, and why do you need to compare and jump while it's just some simple bitwise operations. Here is an implementation in C
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