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error deleting item from list after passing through function


error deleting item from list after passing through function

By : Elliott Klein
Date : November 22 2020, 10:56 AM
around this issue The error message is self-explanatory: at that point it is not a std::list::iterator, it's actually an std::list::iterator*. You must dereference the pointer (as you did just on the previous line).
code :


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Segmentation Fault error when deleting an item of a Linked List

Segmentation Fault error when deleting an item of a Linked List


By : rkb
Date : March 29 2020, 07:55 AM
it fixes the issue I'm trying to implement a Linked List following this example.
code :
if(head->number == _number)
if(head && head->number == _number)
remove() function not deleting the item within ul list

remove() function not deleting the item within ul list


By : Fake Manager
Date : March 29 2020, 07:55 AM
I hope this helps you . Elements in Chrome have a .remove() method which allows for self-removal of an element instead of having to do it from the parent.
So "remove" is a reserved keyword, that's the issue and the reason it removes the element and not executing your function. You need to choose another name for your function.
Error while deleting an item from list row in Xamarin Android

Error while deleting an item from list row in Xamarin Android


By : Cameron Thayer
Date : March 29 2020, 07:55 AM
wish helps you Exception is raised because you are deleting items using tags(index). Instead assign item as Tag to your button. On Click, get item object, remove from array and update List.
Set Tag as:
code :
holder.btnDeleteItem.SetTag("Object", item);
holder.btnDeleteItem.Click += (object sender, EventArgs e) =>
            {
               Item item = (Item) btn.GetTag("Object");
               items.Remove(item);
               context.RunOnUiThread(() => this.NotifyDataSetChanged());

            };
Passing list to pool.map() function in Python returns each character for each item in the list

Passing list to pool.map() function in Python returns each character for each item in the list


By : Diane Alsing
Date : March 29 2020, 07:55 AM
Does that help map is passing one item of each list to function2.
And then, inside function2, you're iterating over that item, getting each character of the string.
code :
values = ["11" ,'22' , '33']
for value in values:
    for item in value:
        print item
def function2(item):
    print item
values = [[value] for value in values]
values = [values]
values = [values[::2], values[1::2]]
Function of semicolon while deleting an item from a list

Function of semicolon while deleting an item from a list


By : Shipra Sangal
Date : March 29 2020, 07:55 AM
hope this fix your issue The semicolon is just a way to put two statements on a single line, but generally doesn't change the behavior of your program.
As others have pointed out, deleting the element at index [10] causes all the following element's indices to be shifted down by one, so any subsequent operations must have any indices they specify adjusted accordingly.
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