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Why is there an extra part when parseUri() a String?


Why is there an extra part when parseUri() a String?

By : user2956546
Date : November 22 2020, 10:56 AM
hop of those help? The docs say that if the URI you are trying to parse was not generated by myIntent.toUri() then it will treat the String as URI and set the action to VIEW:
code :


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Remove extra part in remoteClientAddress string in .xslt in MULE server 3.3.0 CE?

Remove extra part in remoteClientAddress string in .xslt in MULE server 3.3.0 CE?


By : Ramin B.
Date : March 29 2020, 07:55 AM
wish helps you In my configuration.xml in MULE server 3.3.0 CE, I pass MULE_REMOTE_CLIENT_ADDRESS to .xslt file, below I copied my codes : , I don't know anything about Mule, but you could just do this:
code :
<xsl:param  name="remoteClientAddress" />
<xsl:variable name="remoteClientAddressTrimmed"
       select="substring-before(substring-after($remoteClientAddress, '/'), ':')" />
<xsl:value-of select="$remoteClientAddressTrimmed" />
Cannot find module 'parseuri'

Cannot find module 'parseuri'


By : andrea durando
Date : March 29 2020, 07:55 AM
Does that help Well... you should read the error first, if it says you don't have the module "parseuri", install it then.
Make a folder named "node_modules" on the root dir of your project, then go to the console and type npm install parseuri or npm install -g parseuri to make it global.
Why does Network.URI (parseURI) not like the pipe character?

Why does Network.URI (parseURI) not like the pipe character?


By : Hamed. Khodaie Mehr
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You need to use escapeURIString before parsing. isUnescapedInURI will tell you if the character is allowed unescaped in a URI component as mentioned in the documentation.
code :
λ> isUnescapedInURI '|'
False
λ> parseURI $ escapeURIString isUnescapedInURI "http://something.com/foo|bar"
Just http://something.com/foo%7Cbar
replaceAll pastes part of unnecessary extra string

replaceAll pastes part of unnecessary extra string


By : Jirong HU
Date : March 29 2020, 07:55 AM
Does that help You are replacing Book 1;Author 1;11|11 sequence with Book 1;Autor 1;12|12 sequence however the first line ends with 1:11|11. Notice the extra |11 at the end of a line, it won't be processed and will be appended to Book 1;Autor 1;12|12.
To fully replace first line you need:
code :
String old = "Book 1;Autor 1;11|11";
String newS = "Book 1;Autor 1;12|12";
String content = oldContent.replace(old, newS);
SQL Server : find and replace part of a specific part of string that appears more than once in a string

SQL Server : find and replace part of a specific part of string that appears more than once in a string


By : user2258198
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Normalizing addresses can be a slippery slope. You may be surprised on the variations of Blvd. This is why I suggest you take a peek at Address standardization within a database
That mentioned, here is a simple and easy to expand option
code :
Declare @YourTable table (id int,Addr varchar(150))
Insert Into @YourTable values
 (1,'123 Stripe St')
,(2,'555 SW Main St, Providence, RI')


Update @YourTable
 Set Addr = ltrim(rtrim(
            replace(
            replace(' '+Addr+' ',' St ',' Street ')
            ,' St, ',' Street, ')
            ))

Select * from @YourTable
id  Addr
1   123 Stripe Street
2   555 SW Main Street, Providence, RI  -- Notice middle St with a comma.
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