Java: ToString() prints the same hashcode each time

Java: ToString() prints the same hashcode each time

By : user2956435
Date : November 22 2020, 10:56 AM
this one helps. , Try making two instances,
code :
System.out.println(new Point(10, 20));
System.out.println(new Point(10, 20));

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Java: @Overridden toString() doesn't prints anything

Java: @Overridden toString() doesn't prints anything

By : Sherkhan
Date : March 29 2020, 07:55 AM
Any of those help From your code, I can't tell what type of logger you are using (based on the method signature of info(), it does not appear to be a log4j nor a java.util logger), but I suspect that calling
code :
LOGGER.info("added variable - " + variable);
LOGGER.info("added variable - ", variable);
Add toString, hashCode, equals while generating JAXB classes in Java

Add toString, hashCode, equals while generating JAXB classes in Java

By : Russell
Date : March 29 2020, 07:55 AM
I hope this helps . On the Java.net website, you will find the JAXB 2.x Commons project, which provides a common set of JAXB utility plugins, including 4 that should address what you are trying to achieve:
Equals Plugin HashCode Plugin Setters Plugin ToString Plugin
code :
<?xml version="1.0"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
    jaxb:extensionBindingPrefixes="basic equals hashCode toString">
    <!-- ... -->
Java - Overriding hashCode and toString

Java - Overriding hashCode and toString

By : Themba Alex Khumalo
Date : March 29 2020, 07:55 AM
seems to work fine Sure, a1 and a2 have the same hash code, but they weren't considered equal because you didn't override equals to consider two A objects with the same ele to be equal. A map will use equals to the final ruler on equality after it uses the hash code. The map will place both objects in the same bucket, but because they aren't equal, it will keep both.
Override equals so that it returns true if the other object is an A and they both have the same ele. Then you will see that val2 will be returned for both get calls.
Java inheritance why does this toString prints BB and not AB, AB?

Java inheritance why does this toString prints BB and not AB, AB?

By : Yang su
Date : November 21 2020, 11:01 PM
hope this fix your issue There is only one class name per object in java. If you want to know the name of super class, you have to use: getClass().getSuperclass().getSimpleName().
Since both objects are new B(), doesn't matter if you are calling super.toString() or toString(), both will return the name of class B, because getClass() return always the name of the class that you created by using new.
Why doesn't Java expose a Compile time reflection based toString/hashCode/equals?

Why doesn't Java expose a Compile time reflection based toString/hashCode/equals?

By : Phillip Mol
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Java is a very conservative language, to change the default behaviour after 20 years would change existing programs. Which is something that is generally avoided in Java as much as possible. If toString was to always return the value of every field then it opens a program up to two risks, a) the generated string could get very large, ie spam logs and b) get so so large due to a circular reference or big data that it would never end and cause a stack overflow or an out of memory exception (both can be avoided, by adding extra cost/complexity). defaulting to a hash is not useless, as a default behaviour in a debugger it gives clues about object identity rather than equality.. useful for certain classes of bug. Some fields may contain sensitive information, such as passwords or credit card numbers. Such fields should not appear in full in logs. (chrylis)
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