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Error while connecting my login page with the JDBC code


Error while connecting my login page with the JDBC code

By : user2956350
Date : November 22 2020, 10:54 AM
hope this fix your issue Your expectations don't match realty, the method you are calling is declared as returning boolean
code :
public boolean dbConnector(){
public Connection dbConnector(){

    try {
        // Load the JDBC driver
        Class.forName(driverName);
        // Create a connection to the database
        connection = DriverManager.getConnection(url, username, password);
    } catch (ClassNotFoundException e) {
        // Could not find the database driver
        e.printStackTrace();
    } catch (SQLException e) {
        e.printStackTrace();
    }
    return connection;
}


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JDBC result set for code connecting Java and MySQL

JDBC result set for code connecting Java and MySQL


By : Carlos Monzon
Date : March 29 2020, 07:55 AM
I wish this help you You need to call resultcount.next() before calling resultcount.getInt(0);
And it's good practice to close your result sets in a finally clause. Here is generally the structure you would want to use.
code :
//in general use a structure like this:
ResultSet rs = null;
PreparedStatemetn pStmt = null;
try {

 pStmt = conn.prepareStatement("Select * from foo");
 rs = pStmt.executeQuery();
 while (rs.next()) {
    String data = rs.getString(1);
 }
}
catch(Exception e){
 //handle exception
}
finally {
  try {
     if (rs != null) rs.close();
     if (pStmt != null) pStmt.close();
  }
  catch (Exception ignored) {
  }
}
class DbUtil {
    public void closeQuietly(ResultSet rs) {
      try {
         if (rs != null) rs.close();
      }
      catch (Exception ignored) {}
    }

    public void closeQuietly(Statement stmt) {
      try {
         if (stmt != null) stmt.close();
      }
      catch (Exception ignored) {}
    }
}
Error in connecting SpringMVC with JDBC using net.sourceforge.jtds.jdbc.Driver

Error in connecting SpringMVC with JDBC using net.sourceforge.jtds.jdbc.Driver


By : Pat
Date : March 29 2020, 07:55 AM
I wish this helpful for you It looks like that your DB connection URL is not right or DB server is not available. Could you please verify that by logging using some client tool?
Php login page code issue. Login page load message display invalid login

Php login page code issue. Login page load message display invalid login


By : varza
Date : March 29 2020, 07:55 AM
help you fix your problem Thank you for your support and help! My problem got resolved. I have added if($_SERVER["REQUEST_METHOD"] == "POST") and before that POST data from html file.
Connecting firebase to my TextField/Material Login page code

Connecting firebase to my TextField/Material Login page code


By : user3544814
Date : March 29 2020, 07:55 AM
With these it helps this what you can do, this code is for log in button userEmail and userPassword are strings that you get from both text fields
code :
onPressed: () async {
                    try {
                      AuthResult result = await FirebaseAuth.instance
                          .signInWithEmailAndPassword(
                              email: userEmail, password: userPassword);
                      print(result.user.email : userEmail);//#debug statement
                      setState(() {});
                    //navigator push here, to go to next page, if login is successfull
                    } catch (e) {
                      print('error during login is $e'); // #debug
                    }
                  },
@override
  void initState() {
    isUserLoggedIn();
    // TODO: implement initState
    super.initState();
  }

  isUserLoggedIn() async {
    var x = await FirebaseAuth.instance.currentUser();
    if (x != null) {
      // code to be execute if someone is already logged in, take him to next page
    }
  }
error in jdbc code -> com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax

error in jdbc code -> com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax


By : Carhil Matos
Date : March 29 2020, 07:55 AM
will be helpful for those in need com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@gmail.com' at line 1 , The error is here, in listUser():
code :
    // fetch query
    String fetchUser = "SELECT * FROM user WHERE email = " + emailParam;
    pre = conn.prepareStatement(fetchUser);
    // fetch query
    String fetchUser = "SELECT * FROM user WHERE email = ?";
    pre = conn.prepareStatement(fetchUser);
    pre.setString(1, emailParam);
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