logo
down
shadow

What chars cannot be removed from keywords in vim


What chars cannot be removed from keywords in vim

By : user2956176
Date : November 22 2020, 10:54 AM
hop of those help? The default value of 'iskeyword' is a comma-separated list. On unix-like systems, it is:
code :
@,48-57,_,192-255
:set iskeyword-=_
:set iskeyword+=^a


Share : facebook icon twitter icon
preg_match a keyword variable against a list of latin and non-latin chars keywords in a local UTF-8 encoded file

preg_match a keyword variable against a list of latin and non-latin chars keywords in a local UTF-8 encoded file


By : h g
Date : March 29 2020, 07:55 AM
This might help you The problem seems to relate to recognizing word boundaries; the \b construct is apparently not “Unicode aware.” This is what the answers to question php regex word boundary matching in utf-8 seem to suggest. I was able to reproduce the problem even with text containing Latin letters like “é” when \b was used. And the problem seems to disappear (i.e., Arabic words get correctly recognized) when I set
code :
$wstart = '(^|[^\p{L}])';
$wend = '([^\p{L}]|$)';
$regexp = "/" . $wstart . $val . $wend . "/iu";
Regex match when spaces are removed, how to delete the matched chars from the original string with spaces?

Regex match when spaces are removed, how to delete the matched chars from the original string with spaces?


By : Basem Mohammed Fawzy
Date : March 29 2020, 07:55 AM
will be helpful for those in need I think I got to an acceptable solution. I used part of my original code, part of the code by @Abhijit and the main idea behind @wei2912 's code. Thank you all
Here is the code I am going to use:
code :
legal_ids = '^ltd|ltd$|^gmbh|gmbh$|^gesmbh|gesmbh$'

def foo(name, legal_ids):
    #initialize re (company id at beginning or end of string)
    re_code = re.compile(legal_ids)
    #remove spaces from name
    name_stream = name.replace(' ','')
    #search for matches
    comp_id_re = re_code.search(name_stream)
    if comp_id_re:
        #match was found, extract the matching company id
        company_id = comp_id_re.group()
        #remove the id from the string without spaces
        name_stream = re.sub(re_code, '', name_stream).strip()
        if comp_id_re.start()>0:
            #the legal id was NOT at the beginning of the string, proceed normally
            name_stream_it = iter(name_stream)
            final_name = ''.join(next(name_stream_it) if e != ' ' else ' ' for e in name)
        else:
            #the legal id was at the beginning of the string, so do the same as above, but with the reversed strings
            name_stream_it = iter(name_stream[::-1])
            final_name = ''.join(next(name_stream_it) if e != ' ' else ' ' for e in name[::-1])
            #reverse the string to get it back to normal
            final_name = final_name[::-1]
    else:
        company_id = ''
        final_name = name
    return (final_name.strip(), company_id)
When were F# unused reserved keywords removed from the specs?

When were F# unused reserved keywords removed from the specs?


By : Nitish Kafle
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You can read about them in the RFC over at the fslang-design repo. The unreserved keywords are:
method - the F# community is happy with member to introduce methods. constructor - the F# community is happy with new to introduce constructors. atomic - this was related to the fad for transactional memory circa 2006. In F# this would now be a library-defined computation expression. eager - this is no longer needed, it was initially designed to be let eager to match a potential let lazy. object - there is no need to reserve this. recursive - F# is happy using rec. functor - If F# added parameterized modules, we would use module M(args) = .... measure - There is no specific reason to reserve this these days, the [] attribute suffices. volatile - There is no specific reason to reserve this these days, the [] attribute suffices.
RegExp for matching usernames: min 3 chars, max 20 chars, optional underscore in between chars

RegExp for matching usernames: min 3 chars, max 20 chars, optional underscore in between chars


By : nautx
Date : March 29 2020, 07:55 AM
I hope this helps you . I'm attempting to match roblox usernames (which follow these guidelines): , You could use
code :
^(?=^[^_]+_?[^_]+$)\w{3,20}$
^         # start of the string
(?=
    ^     # start of the string
    [^_]+ # not an underscore, at least once
    _?    # an underscore
    [^_]+ # not an underscore, at least once
    $     # end of the string
 )
\w{3,20}  # 3-20 alphanumerical characters
$         # end
let usernames = ['gt_c', 'gt', 'g_t_c', 'gtc_', 'OnlyTwentyCharacters', 'poppy_harlow'];

let alphanumeric = new Set(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '_']);

function isValidUsername(user) {
    /* non-regex version */
    // length
    if (user.length < 3 || user.length > 20)
        return false;

    // not allowed to start/end with underscore
    if (user.startsWith('_') || user.endsWith('_'))
        return false;
        
    // max one underscore
    var underscores = 0;
    for (var c of user) {
        if (c == '_') underscores++;
        if (!alphanumeric.has(c))
            return false;
    }

    if (underscores > 1)
        return false;
        
    // if none of these returned false, it's probably ok
    return true;
}

function isValidUsernameRegex(user) {
    /* regex version */
    if (user.match(/^(?=^[^_]+_?[^_]+$)\w{3,20}$/))
        return true;
    return false;
}

usernames.forEach(function(username) {
    console.log(username + " = " + isValidUsername(username));
});
Chars after dot are removed while executing dynamic sql

Chars after dot are removed while executing dynamic sql


By : ayssegul
Date : March 29 2020, 07:55 AM
I hope this helps . I have a SQL statement like below:- , You need to use Quotename to escape dot in database name
shadow
Privacy Policy - Terms - Contact Us © ourworld-yourmove.org