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Getting content of function (Between curly braces)


Getting content of function (Between curly braces)

By : Rasith
Date : November 22 2020, 10:54 AM
this one helps. I have a class with "n" complex functions like this:
code :
{(?:(?!\n{2,})[\s\S])*}


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Regular expression to match content within curly braces without nested braces breaking it

Regular expression to match content within curly braces without nested braces breaking it


By : dimis
Date : March 29 2020, 07:55 AM
wish helps you I'm currently matching content within a set of curly braces using {([^}]*)}, but it stops working once I add closing other curly braces inside of it. , I think you are looking for that:
code :
{((?:[^{}]|{{[^}]*}})*)}
{(
(?:               # non capturing group
    [^{}]         # all that is not a curly bracket
  |               # OR
    {{[^}]*}}     # a string inside double curly brackets
)*                # zero or more times
)}
{((?>[^{}]+|{{[^}]*}})*)}
{((?:(?=([^{}]+|{{[^}]*}}))\2)*)}
Match content between curly braces than also can contain curly braces

Match content between curly braces than also can contain curly braces


By : user3022160
Date : March 29 2020, 07:55 AM
I wish this help you If I have a string: , You could use this regex also.
code :
\{(?:{[^{}]*}|[^{}])*}
>>> s = 'aaa{bbb}ccc{ddd{eee}fff}ggg'
>>> re.findall(r'\{(?:{[^{}]*}|[^{}])*}', s)
['{bbb}', '{ddd{eee}fff}']
\{(?:(?R)|[^{}])*}
>>> import regex
>>> regex.findall(r'\{(?:(?R)|[^{}])*}', s)
['{bbb}', '{ddd{eee}fff}']
Regex for matching content (function/namespace) between nested curly braces

Regex for matching content (function/namespace) between nested curly braces


By : kevmsterk
Date : March 29 2020, 07:55 AM
it fixes the issue In Jeffrey Friedl's book Mastering Regular Expressions there's a suitable sample on page 436.
How to match nested constructs is also explained at regular-expressions.info or weblogs.asp.net.
code :
{(?>[^{}]+|{(?<x>)|}(?<-x>))*(?(x)(?!))}
Mocha before function - lambda without curly braces errors; lambda with curly braces works

Mocha before function - lambda without curly braces errors; lambda with curly braces works


By : Peter Babus
Date : March 29 2020, 07:55 AM
hop of those help? It says so right there, you weren't returning anything before, you were just using done to specify when the task is done. Now you are returning a Promise (the result of the mockgoose call i'd assume) and it's confusing mocha.
Arrow function runs perfect without curly braces. Added curly braces{ return } and it breaks

Arrow function runs perfect without curly braces. Added curly braces{ return } and it breaks


By : Bhavish Sobrun
Date : March 29 2020, 07:55 AM
this will help You're falling victim to a "trap" in the semicolon insertion rules. After a return, a semicolon is assumed if an expression doesn't start on the same line.
If you change your function as follows, it should work:
code :
function displayMatches () {
    const matchArray = findMatches(this.value, cities)
    console.log(matchArray)
    const html = matchArray.map(place => {
        return `<li>
            <span class="name">${place.city}, ${place.state}</span>
            <span class="population">${place.population}</span>
        </li>`
    }).join('')
    suggestion.innerHTML = html

} 
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