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Parse error: syntax error in concatenation PHP


Parse error: syntax error in concatenation PHP

By : user2956013
Date : November 22 2020, 10:48 AM
I hope this helps you . , you must hide the whole PHP code like this.
code :
 <?php   
      for ($i=$j=0; $i<5; $i++) { 
 ?>

      <div class='card 
          <?php 
              if($i<3){ 
                  echo "delay" . $j += 5; 
             } 
          ?>
      '>

 <?php } ?>


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PHP Syntax error with Youtube API: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING o

PHP Syntax error with Youtube API: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING o


By : SWHandyman
Date : March 29 2020, 07:55 AM
wish of those help The problem in the PHP code you've presented appears to be in the part of it that constructs the YouTube RSS feed URL. It looks like the following:
code :
<?php
// set feed URL
$lang = $_POST['language'];
$query = $_POST['query'] . "%20review";
switch($lang){
    case "English":
        $feedURL = <<<URL
        http://gdata.youtube.com/feeds/api/videos
        ?q=<?php echo $query; ?>
        &v=2
        &format=5
        &lr=en
        URL;
        break;
    case "French":
        $feedURL = <<<URL
        http://gdata.youtube.com/feeds/api/videos
        ?q=<?php echo $query; ?>
        &v=2
        &format=5
        &lr=fr
        URL;
        break;
    case "Spanish":
        $feedURL = <<<URL
        http://gdata.youtube.com/feeds/api/videos
        ?q=$query;
        &v=2
        &format=5
        &lr=es
        URL;
        break;
}
    case "English":
        $feedURL = <<<URL
        http://gdata.youtube.com/feeds/api/videos
        ?q=<?php echo $query; ?>
        &v=2
        &format=5
        &lr=en
URL;
        break;
$lang_codes = array(
    "English" => "en",
    "French"  => "fr",
    "Spanish" => "es"
);

$feedURL = "http://gdata.youtube.com/feeds/api/videos?q=$&v=2&format=5&lr=" . $lang_codes[$lang];
ng-click Error: [$parse:syntax] Syntax Error: Token 'Object' is unexpected, expecting []]

ng-click Error: [$parse:syntax] Syntax Error: Token 'Object' is unexpected, expecting []]


By : mido Hussein
Date : March 29 2020, 07:55 AM
hop of those help? Without looking at the full code, my guess is that you are getting the error because
code :
ng-click='addressPicked("+results[1]+")'
ng-click='addressPicked(results[1])'
AngularJS Error: [$parse:syntax] Syntax Error: Token ',' is unexpected, expecting []] at column 92 of the expression

AngularJS Error: [$parse:syntax] Syntax Error: Token ',' is unexpected, expecting []] at column 92 of the expression


By : Uzair Mehdi
Date : March 29 2020, 07:55 AM
wish of those help OK according to this topic you are not able to use ng-class directly on uib-tabset but you can do this
code :
   <uib-tab-heading ng-class="{'tab-all-products': prodCategory.slideName == 'All products'}">
      <span>{{prodCategory.slideName}}</span>
    </uib-tab-heading>
laravel 5 error : syntax error unexpected 'if' in the middle of concatenation

laravel 5 error : syntax error unexpected 'if' in the middle of concatenation


By : Alvan Zaputra
Date : March 29 2020, 07:55 AM
like below fixes the issue I have this error : error : syntax error, unexpected 'if' (T_IF) when I run this code : , You cannot have your if inside of setting the variable.
code :
$output.='<tr>'.
'<td>'. strtoupper("$search_iy2->air_code").'</td>'.
'<td>'. strtoupper("$search_iy2->name") .'</td>'.
'<td>'. $search_iy2->tkt_no;

if ($search_iy2->tkt_file)  
    $output .= '<a target="_blank" href="tkt_file/'.$search_iy2->tkt_file.'"> &nbsp; TKT </a>';

$output .= '</td>';
Fetch GET request not getting to API on Android Syntax Error: JSON Parse Error unexpected EOF parse@[native code]

Fetch GET request not getting to API on Android Syntax Error: JSON Parse Error unexpected EOF parse@[native code]


By : user3407401
Date : March 29 2020, 07:55 AM
With these it helps Turns out I was using wildcards (%) in my MySql syntax I was passing in the URL string. IOS handled that find, Android did not. Adjusting the backend to process the wildcards made the difference, apparently you cannot use Fetch API on android if you are passing a '%' in the URL string.
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