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By : user2956001
Date : November 22 2020, 10:48 AM
To fix the issue you can do You just need to make sure that the result of rand() isn't 0 so that you won't have to do the conversion to double and division again and again code :
``````int r = rand();
while (r == 0)
r = rand();

u1 = (double) rand() / RAND_MAX;
``````
``````u1 = (double)(rand() + 1U)/(RAND_MAX + 1U);
``````
``````public double nextDouble() {
return (((long)next(26) << 27) + next(27))
/ (double)(1L << 53);
}
``````
``````return (((long)next(27) << 27) + next(27))
/ (double)(1L << 54);
`````` ## Type inference failure when taking the modulus of a random number

By : M2Computing
Date : March 29 2020, 07:55 AM
wish helps you The compiler cannot infer the type in this situation, there are too many unknowns.
Let us call R the output type of rand::random(), and I the type of 20.
code :
``````R: Rand + Rem<I, Ouput=isize>
I: integral variable (i8, u8, i16, u16, i32, u32, i64, u64, isize or usize)
`````` ## How to avoid integer overflow in case of pow function in division with a number?

Date : March 29 2020, 07:55 AM
Hope this helps I don't have time to write a proper answer now; I'll expand this later if I get a chance. The basic idea is to use the grade-school algorithm, working with "digits" that are a power of the denominator. Do a Google search for "Schrage multiplication" or look here for references. ## Best way to generate (random) a division which result is not a decimal number

By : user6402339
Date : March 29 2020, 07:55 AM
I wish this helpful for you Why not generate the result and divisor, then multiply both to get the dividend?
Instead of using 4 and 3 as dividend and divisor, which results in a decimal number when divided, multiply them both to get 12 as dividend and 4 as divisor which once divided gives 3. ## How to avoid repeat random number, I want to generate random number in asp.net in billions but its repeating

By : shikhar
Date : March 29 2020, 07:55 AM
Hope this helps , Try something like that;
code :
``````        var start = 0;//Min range of numbers
var end = 1000;//Max range of numbers
int i = 0;
Random random = new Random();
var numbers = new HashSet<int>();
while(i < 100)//Collect 100 unique numbers
{
var number = random.Next(start, end);
if (!numbers.Contains(number))
{
i++;
}
}
`````` ## How to avoid a specific number when creating a random number in F#?

By : mtai peres
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I'm trying to generate a random number from 0 to 3 for each direction - n, e, s, w. Whatever the previous direction was in the recursive function can't be used again, and I'm trying to figure out the best way to do that. I'd also like to avoid using mutables. Below is what I have so far and it will work but I'm sure there is a better way to do this... , You only want one of 3 values:
code :
``````let nd1 = random.Next 3
let nd = if nd1 >= d then nd1 + 1 else nd1
`````` 