Ruby regex to split user and date text input

Ruby regex to split user and date text input

By : Vincent
Date : November 22 2020, 10:48 AM
should help you out i have user and date data combined in a string. i tried splitting on ' ' (whitespace), but some of the users have spaces in their names. i believe i have a working solution, but don't think it's best practice; i was hoping somebody could point me in the right direction. i'm guessing there is a better way to implement some form of regex. thanks.
code :

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User Input + Ruby + Regex?

User Input + Ruby + Regex?

By : Charles Beyer
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You need to escape the input: http://www.ruby-doc.org/core/classes/Regexp.html
See the method escape.
code :
Ruby regex to split text

Ruby regex to split text

By : codex
Date : March 29 2020, 07:55 AM
will be helpful for those in need I am using the below regex to split a text at certain ending punctuation however it doesn't work with quotes.
code :
"             # literal: a double quote
(?>           # open an atomic group: all that can be between quotes
    [^"\\]+   # all that is not a quote or a backslash
  |           # OR
    \\{2}     # 2 backslashes (the idea is to skip even numbers of backslashes)
  |           # OR
    \\.       # an escaped character (in particular a double quote)
)*            # repeat zero or more times the atomic group
"             # literal double quote
|             # OR
Split input text into even chunks using regex

Split input text into even chunks using regex

By : blaircart
Date : March 29 2020, 07:55 AM
Any of those help I've done everything I can to find the answer to this problem and I'm sure it is simple so forgive me. I have an input string of upper case letters, no spaces, no line feeds, nothing else but letters from A-Z. I'm trying just to split it into letter pairs using Regex.Split. This is what other posts and regex info says it should be , Imagine you have
code :
//              1       10        20        30        40
var letterPairs = Regex.Split(input, "(.{0,2})").Where(p => !string.IsNullOrEmpty(p)).ToList();
Console.WriteLine("["+String.Join(",", letterPairs)+"]");
var letterPairs = Regex.Split(input, ".{0,2}(.{0,2})").Where(p => !string.IsNullOrEmpty(p)).ToList();
var letterPairs = Regex.Split(input, "(.{0,2}).{0,2}").Where(p => !string.IsNullOrEmpty(p)).ToList();
Ruby 2.3. How can I convert User input string into an array, and then split it into individual elements?

Ruby 2.3. How can I convert User input string into an array, and then split it into individual elements?

By : Jim Stoop
Date : March 29 2020, 07:55 AM
will be helpful for those in need Ruby noob here. I've been on this for a couple of hours while, but I can't figure out how to store user input, turn it into an array, and then split the array into separate elements. , use:
code :
puts "Hey! What's up?"

crypt = gets.chomp

p [crypt.split("")]
preg_split regex - need to split user input around mathematical operators

preg_split regex - need to split user input around mathematical operators

By : Paul Langer
Date : March 29 2020, 07:55 AM
hope this fix your issue I need to split a given user string into an array based around mathematical operators. The symbols I need the string splitting around are: , Is this the pattern you are looking for?
code :
preg_match_all("/(\(|-\d+|\d+|-|\+|\/|\*|\))/", $input, $output);
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