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Too many values to unpack during template rendering


Too many values to unpack during template rendering

By : si_ayer_estaba
Date : November 22 2020, 10:48 AM
may help you . choices should be a sequence (iterable to be exact) of key-description pairs.
code :
TEST_TYPE_CHOICES = [
    ('HDFS', 'HDFS'),
    ('HIVE', 'HIVE'),
    ('BOTH', 'Both of HDFS and HIVE'),
]
>>> a, b = ('HDFS', 'HDFS')
>>> a, b = 'HDFS'
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: too many values to unpack
>>> a, b = 'HD'
>>> a
'H'
>>> b
'D'


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w, h = template.shape[::-1] results in Value Error too many values to unpack

w, h = template.shape[::-1] results in Value Error too many values to unpack


By : Ramesh
Date : March 29 2020, 07:55 AM
seems to work fine Im on Python 2.7 (x86) ,Open CV 3.1.0, Windows 7 (x64) , Your image shape returns 3 dimensions
code :
im.shape
>>> (24, 28, 3)
w, h = im.shape[:-1]
>>> (24, 28)
w, h, _ = im.shape
# w is 24, h is 28
Django template : Need 2 values to unpack in for loop; got 8

Django template : Need 2 values to unpack in for loop; got 8


By : Wilbelison Junior
Date : March 29 2020, 07:55 AM
help you fix your problem Be careful to not use list as variable it is depreciated since it is a Python Type Object(reserved)
And the problem is only in your render:
code :
my_list = [(1,2,3,4,5,6,7,8),(1,2,3,4,5,6,7,8),(1,2,3,4,5,6,7,8)]
return render(request, 'accounts/page.html', {'my_list': my_list})
How to unpack different values depending on number of variables to unpack into

How to unpack different values depending on number of variables to unpack into


By : ÔngMập Của MắmLớn
Date : March 29 2020, 07:55 AM
may help you . This is completely doable, but may not be the best application, in your example, of an iterable.
Basically, create a list from your iterable, as in list([*pos]), then slice it as desired like list([*pos])[0:3].
code :
class LatLonOrXYZ:
    def __init__(self, x, y, z, lat, lon):
        self.x, self.y, self.z = x, y, z
        self.lat, self.lon = lat, lon

    def __iter__(self):
        # not sure...
        return iter([self.x, self.y, self.z, self.lat, self.lon])

pos = LatLonOrXYZ(x=0, y=1, z=2, lat=3, lon=4)

x, y, z = list([*pos])[0:3]
lat, lon = list([*pos])[3:5]

print(x, y, z)
print(lat, lon)
0 1 2
3 4
pos = LatLonOrXYZ(x=0, y=1, z=2, lat=3, lon=4)

x, y, z = *LatLonOrXYZ  # 0, 1, 2
lat, lon = *LatLonOrXYZ  # 3, 4
pos = LatLonOrXYZ(x=0, y=1, z=2, lat=3, lon=4)

x, y, z = *pos  # 0, 1, 2
lat, lon = *pos  # 3, 4
pos_1 = LatLonOrXYZ(x=0, y=1, z=2, lat=3, lon=4)
pos_2 = LatLonOrXYZ(x=4, y=3, z=2, lat=1, lon=0)
Iteratively unpack function output - error: too many values to unpack

Iteratively unpack function output - error: too many values to unpack


By : Vlada
Date : March 29 2020, 07:55 AM
I hope this helps you . I wrote a function which returns different outputs and I need to iteratively call the function for each element of an array (passed as an iterable). , Use zip, you don't need the intermediate function:
code :
a, b, c = list(zip(*[(elem, elem+1,elem+2) for elem in it]))
a, b, c = [list(x) for x in zip(*[(elem, elem+1,elem+2) for elem in it])]
>>> a, b, c = list(zip(*[(elem, elem+1,elem+2) for elem in range(100)]))
>>> a
(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99)
>>> b
(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100)
>>> c
(2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101)
a,b,c=[list(x) for x in zip(*[returninput(elem, elem+1,elem+2) for elem in it])]
ValueError: not enough values to unpack (expected 2, got 1) when trying to unpack dict in python for data labeling with

ValueError: not enough values to unpack (expected 2, got 1) when trying to unpack dict in python for data labeling with


By : user3694262
Date : March 29 2020, 07:55 AM
should help you out I created a dictionary that label each api endpoint from my backend to a product group. Currently I'm trying in python 3.7.6 to use this dictionary to further label all data in the csv that I get from NewRelic with data from all transactions (avg latency, request count, etc.). The code is teh following: , Replace your code:
code :
for k, v in doc_dic:
        if k == resp.Action:
            resp.insert(0, "Product Group", v)
for k, v in doc_dic.items():
        if k == resp.Action:
            resp.insert(0, "Product Group", v)
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