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PHP- MySQLI prepare statements


PHP- MySQLI prepare statements

By : user2955661
Date : November 22 2020, 10:40 AM
like below fixes the issue I'm very new to coding and I want to use MySQLi prepare statements for this piece of code, however I've spent hours trying and all i get is a whitescreen. , i managed to fix it with this.
code :
	$stmt = $mysqli->prepare("SELECT COUNT(*) FROM tblUser WHERE username  = ?
																	 AND password  = ?");
				$stmt->bind_param('ss', $username, $password);
				$stmt->execute(); 
				$stmt->bind_result($rowLogin);
				$stmt->fetch();
				$stmt->close();


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Can't use prepare() when using mysqli prepared statements

Can't use prepare() when using mysqli prepared statements


By : Iqbal hossain
Date : March 29 2020, 07:55 AM
like below fixes the issue I'm tryign to create an object orientated approach to a project I'm working on for fun, but I'm having trouble getting my head around the idea of a database class. I'm getting the following error. , You need to add the following method to your class:
code :
public function prepare($query) {
  return $this->connection->prepare($query);
}
public function __call($name, $arguments) {
  return call_user_func_array(array($this->connection, $name), $arguments);
}
Is it really nesseccary to PREPARE statements with PHP's mysqli?

Is it really nesseccary to PREPARE statements with PHP's mysqli?


By : nilan
Date : March 29 2020, 07:55 AM
With these it helps I think you should think about the long term benefit. For example, if in the future you are no longer the developer of that project, the habit of using non-prepared statement will be passed down to the next developer and this:
code :
$id = $_POST['id'];
$result = db_query('SELECT userid, first_name, last_name FROM user 
                WHERE userid = ' . db_escape($id) );
MySQLi multiple prepare statements

MySQLi multiple prepare statements


By : S.Y
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have checked everywhere thoroughly, and have gone through everything possible to find an answer to this. Besides saying "the code doesn't work" which obviously is not enough, I have yet to find anything that will even come close to this. I'm probably going to get downvotes, but let's see how this goes. , Two points:
PHP mysqli prepare statements own class

PHP mysqli prepare statements own class


By : vamsi chand
Date : March 29 2020, 07:55 AM
I wish this helpful for you You can't use $stmt->bind_param() that way. You would need to do argument unpacking because bind_param requires type and then each value as an argument.
code :
final public function newData($sql, $placeholder, $array) {
    $stmt = $this->db->prepare($sql);
    $stmt->bind_param($placeholder, ...$array);
    return $stmt->execute();
}
$sql = "INSERT INTO table (name, data) VALUES (?,?)";

$result = $theDbClass->newData($sql, 'ss', ['foo', 'bar']);
how to get insert_id using mysqli prepare statements

how to get insert_id using mysqli prepare statements


By : Paul Laskin
Date : March 29 2020, 07:55 AM
Does that help How can I get the insert_id of the last record using mysqli prepare statement, for example following? , $new_id = $this->mysqli->insert_id; (after $stmt->execute())
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