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How to implement MaxOrDefault(x => x.SomeInt) LINQ extension?


How to implement MaxOrDefault(x => x.SomeInt) LINQ extension?

By : user100328
Date : November 22 2020, 10:40 AM
wish help you to fix your issue When calling .Max(x => x.SomeInt) on an IEnumerable, you commonly are happy to return "0" if the enumerable contains no elements. However LINQ's implementation of .Max(x => x.SomeInt) crashes as the sequence contains no elements. , Here is what I consider a better/neater implementation:
code :
public static TResult MaxOrDefault<T, TResult>(this IEnumerable<T> enumerable, Func<T, TResult> func)
{
    return enumerable.Select(func).DefaultIfEmpty().Max();
}


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Uncertain of how to implement a specific extension to nHibernate with LINQ

Uncertain of how to implement a specific extension to nHibernate with LINQ


By : user3116924
Date : March 29 2020, 07:55 AM
hop of those help? Yes you are right, the question is a bit vague but I'll try to address your points.
1) You are not really extending the Query object. The extension that you would be writing would actually be against IQueryable so...
code :
    public static IQueryable<Post> MySecurityExtension(this IQueryable<Post> repository, string currentUser)
    {
        return repository.Where(p => p.User == currentUser);
    }
LINQ "MaxOrDefault"?

LINQ "MaxOrDefault"?


By : Frank
Date : March 29 2020, 07:55 AM
will be helpful for those in need DefaultIfEmpty method should help:
code :
int new_id = C_Movement.list.Select(x => x.id).DefaultIfEmpty(-1).Max()+1;
C++ How to implement: myInstance << "abc" << someInt << std::endl

C++ How to implement: myInstance << "abc" << someInt << std::endl


By : fish
Date : March 29 2020, 07:55 AM
seems to work fine I have my custom class in C++: , You can use something like this:
code :
class MyClass
{
public:
    MyClass() : logfile("logfile.log", std::ios::app) {}

    template<typename T>
    friend MyClass& operator<<(MyClass& obj, const T& data);

    private:
        std::ofstream logfile;
};

template<typename T>
MyClass& operator<<(MyClass& obj, const T& data) {
    obj.logfile << data;
    return obj;
}

int main() {
    MyClass obj;

    obj << "Hello\n"; 
    obj << 123 << " World\n";
}
MyClass *obj = new MyClass;

*obj << "Hello\n"; 
*obj << 123 << " World\n";
Confused about how to implement extension methods in LINQ to Objects

Confused about how to implement extension methods in LINQ to Objects


By : user3804195
Date : March 29 2020, 07:55 AM
wish of those help Well, it's not entirely clear which bit is causing the problem. If you've already done the Median method, then you can change query to:
Custom Extension-Function to implement "IN" in c# (LINQ-2-Entities)

Custom Extension-Function to implement "IN" in c# (LINQ-2-Entities)


By : user5701097
Date : March 29 2020, 07:55 AM
To fix this issue
How can I write correspondend custom In(...) Extension-Function?
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