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Regular expression to match part of word


Regular expression to match part of word

By : user2955617
Date : November 22 2020, 10:40 AM
help you fix your problem This expression: REP(?:ORTS?)?
Will match:
code :
REP      (?# match REP literally)
(?:      (?# start non-capturing group)
  ORT    (?# match ORT literally)
  S?     (?# optionally match S literally)
)?       (?# close optional non-capturing group)


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Perl one liner + regular expression to match part of word

Perl one liner + regular expression to match part of word


By : EcxaByte
Date : March 29 2020, 07:55 AM
To fix this issue Here are some examples of IP regexp matching from O'Reilly's Regular Expressions Cookbook:
Simple regex to check for an IP address:
code :
^(?:[0-9]{1,3}\.){3}[0-9]{1,3}$
^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}↵
(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$
\b(?:[0-9]{1,3}\.){3}[0-9]{1,3}\b
\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}↵
(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b
^([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})$
^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.↵
(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.↵
(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.↵
(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$
Regular expression exact part of letters match in middle of the word including Dot[.]

Regular expression exact part of letters match in middle of the word including Dot[.]


By : Sabe
Date : March 29 2020, 07:55 AM
Any of those help Here is a demo - Regex101
You can modify this by replacing the "bc" with your search string.
code :
\w*bc\w*\.\d*
\w*bc\.\d*
How would I construct a regular expression to match a word, unless it's a part of a specific pattern?

How would I construct a regular expression to match a word, unless it's a part of a specific pattern?


By : Cyprian Bitner
Date : March 29 2020, 07:55 AM
To fix this issue I have a regex that works while I want to match 'android' not followed by 'mobile' , You may perform the check without a lookbehind:
code :
var strs =[ "my-custom-android some thing else", "my-custom-android mobile some thing else android", "mobile android", "android mobile", "another android story" ];
var patt = /(my-custom-)?android(?!.*mobile)/i;
for (var str of strs) {
  var res = str.match(patt);
  if(res && res[1] === undefined)
  { // do something
     console.log(str, "=> MATCHED");
  } else {  // DON'T do anything
    console.log(str, "=> NOT MATCHED"); 
  }
}
Extended Regular Expression: Find a Word That is Not Part of Another Word

Extended Regular Expression: Find a Word That is Not Part of Another Word


By : user2031346
Date : March 29 2020, 07:55 AM
will be helpful for those in need Perl regexes support negative lookahead, the (?!) feature you tried to use. It's the ideal way to express the idea of "foo but not foobar".
code :
grep -P 'foo(?!bar)'
grep -E 'foo($|[^b]|b($|[^a]|a($|[^r])))'
Regular Expression, how to find a word that is not a part of a bigger word

Regular Expression, how to find a word that is not a part of a bigger word


By : Coder
Date : March 29 2020, 07:55 AM
Does that help You need to use the word boundary anchor \b to make sure you don't match part of a word. The regex would look like this:
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