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Taking information from a file and organizing it into constants


Taking information from a file and organizing it into constants

By : user2955435
Date : November 22 2020, 10:40 AM
Hope this helps You should compare strings not by using == but by using the equals method e.g.
str[0] == "username"
code :


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Organizing project files and using global constants within modules

Organizing project files and using global constants within modules


By : Ahmet Bingazi
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , If you make the whole thing a package and also make cls a package (by providing __init__.py files in each directory), then from levels.py you can do from ..game import someConstant.
Organizing code for Testing with Constants from a Configuration File

Organizing code for Testing with Constants from a Configuration File


By : dennis
Date : March 29 2020, 07:55 AM
I hope this helps . My idea, is really simple, use optional keyword arguments. Here is a little example, what I'm talking about:
code :
# collect, the constants to a dictionary,
# with the proper key names
d = dict(a=1, b=2, c=3)

# create functions, where you want to use the constants
# and use the same key-names as in dictionary, and also
# add '**kwargs' at the end of the attribute list
def func1(a, b, d=4, **kwargs):
    print a, b, d

def func2(c, f=5, **kwargs):
    print c, f

# now any time, you use the original dictionary
# as an argument for one of these functions, this
# will let the function select only those keywords
# that are used later
func1(**d)
# 1 2 4
func2(**d)
# 3 5
# Your parsing, reading and storing functions goes here..

# Now create your dictionary
constants = dict(
    host  = DB_HOST,
    pnum  = DB_PORT_NUMBER,
    num   = DB_NUMBER,
    serv  = IN_SERVICE,
    data  = IN_DATA
)
import configuration as cf

def main(host, pnum, num, serv, data, **kwargs):
    intermediate_function(
        host, pnum, num, 'other', 'params', 'here'
    )

def intermediate_function(host, pnum, num, *args):
    pass

# Now, you can call this function, with your
# dictionary as keyword arguments
if __name__ == '__main__':
    main(**cf.constants)
{
    "host"  : "DB_HOST",
    "pnum"  : "DB_PORT_NUMBER",
    "num"   : "DB_NUMBER",
    "serv"  : "IN_SERVICE",
    "data"  : "IN_DATA"
}
import json

with open('conf.json') as conf:
    # JSON parser will convert it to dictionary
    constants = json.load(conf)
Organizing and printing information by a specific row in a csv file

Organizing and printing information by a specific row in a csv file


By : Deva Beva
Date : March 29 2020, 07:55 AM
Does that help This is a problem that you solve with a dictionary; which will accumulate your items by the last name (family name) of your file.
The second thing you have to do is accumulate a total of each type of meal - keeping in mind that the data you are reading is a string, and not an integer that you can add, so you'll have to do some conversion.
code :
import csv

d = dict()

with open(r'd:/file.csv') as f:
    reader = csv.reader(f)
    for row in reader:
        # if the family name doesn't
        # exist in our dictionary,
        # set it with a default value of a blank dictionary
        if row[2] not in d:
            d[row[2]] = dict()

        # If the meal type doesn't exist for this
        # family, set it up as a key in their dictionary
        # and set the value to int value of the count
        if row[1] not in d[row[2]]:
            d[row[2]][row[1]] = int(row[0])
        else:
            # Both the family and the meal already
            # exist in the dictionary, so just add the
            # count to the total
            d[row[2]][row[1]] += int(row[0])
{'Johnsons': {'Chicken': 3, 'Steak': 2, 'Veggie': 1},
 'Martins': {'Fish': 2, 'Steak': 1},
 'Smiths': {'Veggie': 4}}
for family,data in d.iteritems():
   print('{}'.format(family))
   for meal, total in data.iteritems():
       print('{} {}'.format(total, meal))
Johnsons
3 Chicken
2 Steak
1 Veggie
Smiths
4 Veggie
Martins
2 Fish
1 Steak
Taking information by line from a file to tuple

Taking information by line from a file to tuple


By : mc6e
Date : March 29 2020, 07:55 AM
will be helpful for those in need I'm doing a python decryting program for a school project. So first of all, i have a function who takes a file as argument. Then i must take all the line by line and return a tuple. This file containt 3 things : -a number(whatever it's), -the decrypted text, -the crypted text) , You could try this to avoid the '\n' characters at the end
code :
import sys
fileName = sys.argv[-1]
def load_data(fileName):
    tuple = ()
    data = open(fileName, 'r')
    content = data.readlines()
    for i in content:
        tuple += (i.strip(''' \n'"'''),)
    return tuple

print(load_data(fileName));
Getting JSON information from URL, then putting and organizing JSON into a CSV File

Getting JSON information from URL, then putting and organizing JSON into a CSV File


By : user2935021
Date : March 29 2020, 07:55 AM
like below fixes the issue I need to get JSON information from an API and then populate an excel file(through CSV) with its organized information. The part that confuses me is organizing the data into the excel (CSV) file, the json is only printing on one line. Could I have an example of how to do this? I am very confused. , Let's say your JSON looks like this:
code :
{"foo":"bar", "baz":"qux"}
foo,baz
bar,qux
public class MyBean { 
    @JsonProperty
    private String foo

    @JsonProperty
    private String baz

}
ObjectMapper om = new ObjectMapper();
MyBean b = om.readValue(jsonText, MyBean.class)
String csv = "foo,baz\n" + b.getFoo() + "," + b.getBaz();
BufferedWriter writer = new BufferedWriter(new FileWriter(fileName));
writer.write(csv);
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