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See if length between two equal numbers in deque is even


See if length between two equal numbers in deque is even

By : DeltaFlight
Date : November 22 2020, 10:40 AM
I think the issue was by ths following , I have a deque and I want to find if the number of ints between two equal numbers is even. For example:7,13,4,6,4,13,8,10 should be false and 1,3,5,3,4,8,7,9,6,5,7 should be true. I think my program is correct, but or some reason it outputs true for both cases. Any ideas why? PS: I'm not good with iterators. , You have an off-by-one error here:
code :
if(*i == *j && (j-i)%2 == 0)
if (*i == *j && (j-i+1)%2 == 0)
if (*i == *j && (j-i)%2 == 1)
bool isJoined(const deque<int>& deq)
{
    for (size_t i = 0; i < deq.size(); ++i) {
        for (size_t j = i+1; j < deq.size(); ++j) {
            if (deq[i] == deq[j] && (j-i)%2 == 1) {
                return true;
            }
        }
    }

    return false;
}
for (size_t j = i+1; j < deq.size(); j += 2) {
    // already enforcing an even number of numbers in bewteen
    if (deq[i] == deq[j]) return true; 
}


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Round all numbers in file to equal length in Bash?

Round all numbers in file to equal length in Bash?


By : Guzzilar
Date : March 29 2020, 07:55 AM
I wish this helpful for you Is there easy way how to round floating numbers in a file to equal length? The file contains other text not only numbers. , Bash
code :
#!/bin/bash
shopt -s extglob
while read -r line
do
  set -- $line
  for((i=1;i<=${#};i++))
  do
    s=$(eval echo \${${i}})
    case "$s" in
     +([0-9]).+([0-9]) ) s=$(printf "%.2f " $s);;
    esac
    printf "%s " $s
  done
  echo
done <"file"
$ cat file
bla1 bla 2 bla 3.4689 bla bla bla 4.39223 bla.
words ..... 2.14 blah blah 4.5667 blah

$ ./shell.sh
bla1 bla 2 bla 3.47 bla bla bla 4.39 bla.
words ..... 2.14 blah blah 4.57 blah
matplotlib (equal unit length): with 'equal' aspect ratio z-axis is not equal to x- and y-

matplotlib (equal unit length): with 'equal' aspect ratio z-axis is not equal to x- and y-


By : AJFleming
Date : March 29 2020, 07:55 AM
wish of those help I believe matplotlib does not yet set correctly equal axis in 3D... But I found a trick some times ago (I don't remember where) that I've adapted using it. The concept is to create a fake cubic bounding box around your data. You can test it with the following code:
code :
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.gca(projection='3d')
ax.set_aspect('equal')

X = np.random.rand(100)*10+5
Y = np.random.rand(100)*5+2.5
Z = np.random.rand(100)*50+25

scat = ax.scatter(X, Y, Z)

# Create cubic bounding box to simulate equal aspect ratio
max_range = np.array([X.max()-X.min(), Y.max()-Y.min(), Z.max()-Z.min()]).max()
Xb = 0.5*max_range*np.mgrid[-1:2:2,-1:2:2,-1:2:2][0].flatten() + 0.5*(X.max()+X.min())
Yb = 0.5*max_range*np.mgrid[-1:2:2,-1:2:2,-1:2:2][1].flatten() + 0.5*(Y.max()+Y.min())
Zb = 0.5*max_range*np.mgrid[-1:2:2,-1:2:2,-1:2:2][2].flatten() + 0.5*(Z.max()+Z.min())
# Comment or uncomment following both lines to test the fake bounding box:
for xb, yb, zb in zip(Xb, Yb, Zb):
   ax.plot([xb], [yb], [zb], 'w')

plt.grid()
plt.show()
Count length of sequence of equal numbers in a vector

Count length of sequence of equal numbers in a vector


By : Dinara Shadyarova
Date : March 29 2020, 07:55 AM
To fix the issue you can do Consider a vector c(1,1,1,0,1,1). , Use rle:
code :
x <- c(1,1,1,0,1,1)
rle(x)
# Run Length Encoding
#  lengths: int [1:3] 3 1 2
#  values : num [1:3] 1 0 1
Is possible to use std::deque::push_back() and std::deque::front()/std::deque::pop_front() on different threads without

Is possible to use std::deque::push_back() and std::deque::front()/std::deque::pop_front() on different threads without


By : yesimbig
Date : March 29 2020, 07:55 AM
wish helps you If you are not synchronizing between readers and writers, there is a possibility of data corruption.
So the answer in general is NO.
Algorithm to divide array of length n containing numbers from 1 to n (no repetition) into two equal sum

Algorithm to divide array of length n containing numbers from 1 to n (no repetition) into two equal sum


By : Nosta
Date : March 29 2020, 07:55 AM
I wish this help you As per your requirements, we conclude the array will always contain numbers 1 to N. So if Array.Sum()==Even the answer is YES, otherwise NO.
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