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Loading json data with an AngularJS factory


Loading json data with an AngularJS factory

By : user2955424
Date : November 22 2020, 10:40 AM
To fix this issue You forgot to pass the name of the factory in the array. Typically you pass an array whose elements consist of a list of strings followed by the function itself. Be sure to keep the array in sync with the parameters in the function declaration. This way the injector knows what services to inject into the function.
code :
myApp.controller('smController', ['$scope', 'stadtMobilRates', function($scope, stadtMobilRates) {
 when('/sm', {
      templateUrl: 'partials/sm.html',
      controller: 'smController',
      resolve:{
              load:function(stadtMobilRates){
                  return stadtMobilRates.LoadData();
          }
    }).
myApp.factory('stadtMobilRates', function ($q, $http) {
var mobilRates = null;

function LoadData() {
    var defer = $q.defer();
    $http.get('stadtmobilRates.json').success(function (data) {
        mobilRates = data;
        defer.resolve();
    });
    return defer.promise;
}

return {
    GetData: function () { return mobilRates ; },
    LoadData:LoadData
}
});
myApp.controller('smController', ['$scope', 'stadtMobilRates', function($scope, stadtMobilRates) 
{
     var stadtmobilRates = stadtMobilRates.GetData();
});


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I'm getting TypeError: Cannot call method 'slice' of undefined when loading data from factory ng-Table AngularJS

I'm getting TypeError: Cannot call method 'slice' of undefined when loading data from factory ng-Table AngularJS


By : janek
Date : March 29 2020, 07:55 AM
Hope that helps You need to resolve $defer within table getData after the ajax has completed. As it stands right now if you were to log filteredData to console, it will be undefined, thus it can't be sliced.
Try moving userData.getUsers to:
code :
getData: function ($defer, params) {
     /* make ajax call */
    userData.getUsers(function(users) {
        /* now we have data to work with*/
        $scope.users = users;

        var filteredData = $filter('filter')(users, $scope.filter);
        var orderedData = params.sorting() ? $filter('orderBy')(filteredData, params.orderBy()) : filteredData;
        /* and can resolve table promise  */
        $defer.resolve(orderedData.slice((params.page() - 1) * params.count(), params.page() * params.count()));

    })

}
factory not displaying json data angularjs

factory not displaying json data angularjs


By : liushangdev
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I can't seem to display any JSON data from my factory. I'm pretty sure the contractors.json file is loading correctly because the console complained about its syntax a few times. My grunt watch isn't giving me any errors, nor is the console. I'm new to angular and I'm not sure what is wrong. , you did not return the promise:
code :
var deferred = $q.defer();
    $http.get('scripts/contractors.json').success(function(data){
      deferred.resolve(data);
    }).error(function(){
      //
      // !!!! here is your mistake! 
      // You only return the promis if an error occured.
      // 
      return deferred.promise;
    });
var deferred = $q.defer();
$http.get('scripts/contractors.json').success(function(data){
    deferred.resolve(data);
}).error(function(){
   deferred.reject();
});
return deferred.promise;
AngularJS Factory loading data on each click

AngularJS Factory loading data on each click


By : เนส เอง
Date : March 29 2020, 07:55 AM
I hope this helps . You can try this, it initially returns an empty array that will be populated when $http.get() returns and it re-uses the array each time it is called:
code :
myApp.factory('modelFactory', function($http){
  var factory = {};

  factory.getPeople = function () {
    if (typeof(factory.people) == "undefined") {
      factory.people = [];
      $http.get('data.json').success(function(result) {
        var i = 0;
        for (i = 0; i < result.length; i++) {
          factory.people.push(result[i]);
        }
      });
    }
    return factory.people;
  };

  return factory;

});
$scope.people = modelFactory.getPeople();
AngularJS, Display Json Data With Ng-Repeat and Ng-Factory

AngularJS, Display Json Data With Ng-Repeat and Ng-Factory


By : user3777734
Date : March 29 2020, 07:55 AM
To fix this issue I am a beginner at Javascript and Angular, and I'm trying to implement AngularJS on my website. I have watching tutorials on CodeSchool, Egghead etc. But I am stack at very beginning. , I would do your factory this way :
code :
angular.module('nasuh',[])
.factory('MY', function($http){
     var factory = {};
     var url = '/uzak/remote.php?callback=JSON_CALLBACK';
     //I return the $http promise directly when you use MY.isimler
     factory.isimler = $http.get(url);
     return factory;
    })
.controller('nbgCtrl', function($scope, MY) {
         //I handle here the success of the $http call
         MY.isimler.success(function(alHemen){
              $scope.mangas = alHemen;
         });  
     })
      $http.get(url).success(function(data) {
          alHemen = data;
      });
      return alHemen;
$stateProvider
.state('icerik', {
  url: "/icerik",
  templateUrl: "icerik.html",
  controller: "nbgCtrl",
  resolve: {
     isimler : function(MY){
        return MY.isimler;
     }
  }
})
.controller('nbgCtrl', function($scope, isimler) {
     $scope.mangas = isimler;  
 })
Loading JSON files via Azure Data Factory

Loading JSON files via Azure Data Factory


By : user3191051
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further The error message is clear enough when it says "All columns of the table must be specified...". This means that the table in the data warehouse has more columns than what you are seeing in the preview of the json file. You will need to create a table in the data warehouse with the same columns that are shown in the preview of the json files.
If you need to insert them in a table with more fields, create a "staging" table with the same columns as the json file, and then call a stored procedure to insert the content of this staging table in the corresponding table.
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