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Writing the contents of a map through operator overloading


Writing the contents of a map through operator overloading

By : user2955396
Date : November 22 2020, 10:40 AM
seems to work fine Your operator<< for stack is popping all of the elements off of the stack, so the stack is empty by the time you make a copy of it to put in the map.
To demonstrate, if I change your main() to this:
code :
    int main() {
        stack<int> s2;
        s2.push(1);
        s2.push(2);
        cout << s2.size() << '\n';
        cout << s2;
        cout << s2.size() << '\n';
    }
2
{|2||1|}
0
    ostream& operator<<(ostream& out, stack<T> &s){
        stack<T> scopy = s;
        out<<"{";
        while(!scopy.empty()) {
            out<<"|"<<scopy.top()<<"|";
            scopy.pop();    
        }
        out<<"}\n";
        return out;
    }


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Is there a way to print out the contents of a std::list without overloading the << operator?

Is there a way to print out the contents of a std::list without overloading the << operator?


By : Anthony Gonsalvis
Date : March 29 2020, 07:55 AM
should help you out You can always turn recursion into iteration. Here's with an auxiliary queue:
code :
std::deque<Tree *> todo;

todo.push_back(t);

while (!todo.empty())
{
    Tree * p = todo.front();
    todo.pop_front();

    std::cout << p->rule << std::endl;

    todo.insert(todo.end(), p->children.begin(), p->children.end());
}
for (std::deque<Tree *> todo { { t } }; !todo.empty(); )
{
    // ...
}
Overloading operator '=' and [] for writing to position in the file

Overloading operator '=' and [] for writing to position in the file


By : GhostOverload
Date : March 29 2020, 07:55 AM
it fixes the issue The usual solution would be for the operator[] to return a proxy, along the lines of:
code :
class UserFile
{
    //...
    char get( int index ) const { ... }
    void set( int index, char newValue ) { ... }
    class Proxy
    {
        UserFile* myOwner;
        int myIndex;
    public:
        Proxy( UserFile* owner, int index )
            : myOwner( owner )
            , myIndex( index )
        {
        }
        Proxy const& operator=( char ch ) const
        {
            myOwner->set( myIndex, ch ):
            return *this;
        }
        operator char() const
        {
            return myOwner->get( myIndex );
        }
    };
    Proxy operator[]( int index )
    {
        return Proxy( this, index );
    }
};
printf( "%c", static_cast<char>( file[42] ) );
compare string with a number without writing too many operator overloading functions

compare string with a number without writing too many operator overloading functions


By : user3652509
Date : March 29 2020, 07:55 AM
around this issue I assume that you are interested in knowing how can you provide operators relating a custom type to e.g. int without overloading all operators. One way to achieve that is to provide an implicit conversion to a type to which you want to relate your custom type (in this case int). See the example below.
code :
#include <iostream>
using namespace std;

class Foo
{
 public:
  Foo(int val): _val(val)
  {}

  operator int()
  {
    return _val;
  }

 private:
  int _val;
};


int main()
{
  Foo foo(2);

  cout << foo << endl;
  cout << (foo == 2) << endl;
  cout << (foo > 3) << endl;
}
2
1
0
#include <boost/lexical_cast.hpp>
#include <vector>

int main(int /*argc*/, char * argv[])
{
    using boost::lexical_cast;
    using boost::bad_lexical_cast;

    std::vector<short> args;

    while (*++argv)
    {
        try
        {
            args.push_back(lexical_cast<short>(*argv));
        }
        catch(const bad_lexical_cast &)
        {
            args.push_back(0);
        }
    }
}
Overloading << operator to print vector contents

Overloading << operator to print vector contents


By : Kumar Krishnan
Date : March 29 2020, 07:55 AM
I hope this helps . The complaint was that while your function to iterate over and print the vector contents may have been correct, the actual object contained by the vector did not have an operator<< specified.
You need to have one.
Operator overloading:how in unary operator overloading function return is working in this code?

Operator overloading:how in unary operator overloading function return is working in this code?


By : fserron
Date : March 29 2020, 07:55 AM
should help you out
if a instance of Distance is to be returned in operator-() function shouldn't it be returned like new Distance(feet,inches)
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