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Pass ID to another URL


Pass ID to another URL

By : user2955395
Date : November 22 2020, 10:40 AM
Any of those help Looking to achieve the following with a rewrite: , You can put this code in your htaccess (located in sub folder)
code :
RewriteEngine On
RewriteBase /sub/

# redirect /sub/processing.php?id=XXX to /sub/details/XXX
RewriteCond %{THE_REQUEST} /processing\.php\?id=([^\s&]+)\s [NC]
RewriteRule ^ details/%1? [R=301,L]

# internally rewrite /sub/details/XXX to /sub/processing.php?id=XXX
RewriteRule ^details/([^/]+)$ processing.php?id=$1 [L]
RewriteCond %{THE_REQUEST} /processing\.php\?id=([^\s&]+)\s [NC]
RewriteRule ^ details/%1? [R=301,L]


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Is there a language with native pass-by-reference/pass-by-name semantics, which could be used in modern production appli

Is there a language with native pass-by-reference/pass-by-name semantics, which could be used in modern production appli


By : actouf
Date : March 29 2020, 07:55 AM
may help you . Haskell has call-by-need as its default (and indeed only) evaluation strategy.
Now, you asked for two things: call-by-name and modern. Well, Haskell is a pure language and in a pure language call-by-name and call-by-need are semantically the same thing, or more precisely they always have the same result, the only difference being that call-by-need is usually faster and at worst only a constant factor slower than call-by-name. And Haskell surely is a modern language: it is merely 23 years old and in many of its features it is actually 10 years ahead of many languages that were created just recently.
In CCCallFuncND we pass pointers. Is it a good practice to pass pointer of local scope

In CCCallFuncND we pass pointers. Is it a good practice to pass pointer of local scope


By : TDev
Date : March 29 2020, 07:55 AM
like below fixes the issue It is not a good practice. You can pass, but you can't use it if you didn't run the CCCallFuncND immediately. if you put it in to a CCSequence and run it later, the void* will pointing to some invalid address.
Pass-by-value vs pass-by-reference vs pass-by-value-result

Pass-by-value vs pass-by-reference vs pass-by-value-result


By : user2142344
Date : March 29 2020, 07:55 AM
around this issue The first two should be pretty straightforward, the last one is probably throwing you because it's not really a C++ supported construct. It's something that had been seen in Fortran and Ada some time ago. See this post for more info
As for your results, I think this is what you would get:
code :
5
x = 5,
a = 2 * 5 + 1 = 11
b = 11 - 1 = 10
a = 3 * 10 - 10 = 20;  // remember, a and b are the same reference!
x = 20
void main()
{
    int x = 5;
    int copy = x;
    foo (copy,copy);  // copy is passed by reference here, for sake of argument
    x = copy;
    print (x);      
}
void foo (int a, int b)
{
    a = 2 * b + 1;
    x = a - 1;      // we'll assume x is globally accessible
    a = 3 * a - b;
}
a = 2 * 5 + 1 = 11
x = 11 - 1 = 10  // this no longer has any effect on the final result
a = 3 * 11 - 11 = 22
x = 22
c++ pass-by-value, pass-by-reference or pass by value result

c++ pass-by-value, pass-by-reference or pass by value result


By : user3232235
Date : March 29 2020, 07:55 AM
this will help Function inc does not change the original values of array a. It accepts arguments by values that is it deals with copies of the arguments.
If you want that the function would change the arguments it should be defined like
code :
void inc (int &x,int &y ){
    x++;
    y++;
}
i = 0;
inc (a[i],a[i]);
3 
1
difference between Pass-by-value pass-by-reference and pass-by-

difference between Pass-by-value pass-by-reference and pass-by-


By : chandra
Date : March 29 2020, 07:55 AM
it should still fix some issue First of all, when you call a function (or procedure, whatever you name it), a new call stack is created. On that call stack, the parameters are assigned to values (parameters are the ones which is part of your function signature. Usually we call them 'formal parameters', like the x y z in your above procedure f). What they are assigned to is according to the actual arguments by which the function is invoked.
If they are passed by values, the formal parameters are assign to the values of the arguments. That means, the values of the actual arguments are copied to the formal parameters. Any further operations on the formal parameters does not affect the argument at all. In your example, y is assigned to the value of a[1], which is 10. In the function's body, y is reassigned, but nothing happened to a[1] anymore.
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