C RUBY-ON-RAILS MYSQL ASP.NET DEVELOPMENT RUBY .NET LINUX SQL-SERVER REGEX WINDOWS ALGORITHM ECLIPSE VISUAL-STUDIO STRING SVN PERFORMANCE APACHE-FLEX UNIT-TESTING SECURITY LINQ UNIX MATH EMAIL OOP LANGUAGE-AGNOSTIC VB6 MSBUILD

# How to represent double type number in binary form?

By : Liz Hurly
Date : November 22 2020, 10:38 AM
With these it helps How can I represent double type number in binary form, for example: , You can do the following:
code :
``````hexdec = num2hex(dec);
bin = hexToBinaryVector(hexdec);
``````
``````hexToBinaryVector(num2hex(pi))
ans =
1100000000001001001000011111101101010100010001000010110100011000
``````

Share :

## how to represent out of range number in binary?

By : Anupam Joshi
Date : March 29 2020, 07:55 AM
it should still fix some issue You use more bits.
The range -128 to +127 is 256 unique values, which is 8 bits. If you need a larger range, you need more bits.

## convert 64-bit binary string representation of a double number back to double number in c++

By : jimmy james
Date : March 29 2020, 07:55 AM
Does that help I have a IEEE754 Double precision 64-bit binary string representation of a double number. example : double value = 0.999; Its binary representation is "0011111111101111111101111100111011011001000101101000011100101011" , C string solution:
code :
``````#include <cstring>   // needed for all three solutions because of memcpy

double bitstring_to_double(const char* p)
{
unsigned long long x = 0;
for (; *p; ++p)
{
x = (x << 1) + (*p - '0');
}
double d;
memcpy(&d, &x, 8);
return d;
}
``````
``````#include <string>

double bitstring_to_double(const std::string& s)
{
unsigned long long x = 0;
for (std::string::const_iterator it = s.begin(); it != s.end(); ++it)
{
x = (x << 1) + (*it - '0');
}
double d;
memcpy(&d, &x, 8);
return d;
}
``````
``````template<typename InputIterator>
double bitstring_to_double(InputIterator begin, InputIterator end)
{
unsigned long long x = 0;
for (; begin != end; ++begin)
{
x = (x << 1) + (*begin - '0');
}
double d;
memcpy(&d, &x, 8);
return d;
}
``````
``````#include <iostream>

int main()
{
const char * p = "0011111111101111111101111100111011011001000101101000011100101011";
std::cout << bitstring_to_double(p) << '\n';

std::string s(p);
std::cout << bitstring_to_double(s) << '\n';

std::cout << bitstring_to_double(s.begin(), s.end()) << '\n';
std::cout << bitstring_to_double(p + 0, p + 64) << '\n';
}
``````

## Which C datatype can represent a 40-bit binary number?

By : TakeItEasy
Date : March 29 2020, 07:55 AM
To fix the issue you can do If you're using a C99 or C11 compliant compiler, then use int_least64_t for maximum compatibility. Or, if you want an unsigned type, uint_least64_t. These are both defined in
usually also defines int64_t, but since it's not required by the standard, it may not be defined in every implementation. However:

## Python: Choose number of bits to represent binary number

By : ricompute
Date : March 29 2020, 07:55 AM
With these it helps Use the Format String Syntax:
code :
``````>>> format(1, '#04b')
'0b01'
>>> format(1, '#05b')
'0b001'
>>> format(1, '#06b')
'0b0001'
``````

## Represent a Number as a Binary in C#

By : albertman
Date : March 29 2020, 07:55 AM
should help you out To determine which checkboxes should be checked, use the bitwise AND operator:
code :
``````Checkbox1.Checked = value & 1;
Checkbox2.Checked = value & 2;
Checkbox3.Checked = value & 4;
Checkbox4.Checked = value & 8;
``````