How do I get .NET's Path.Combine to convert forward slashes to backslashes?
By : user2100872
Date : March 29 2020, 07:55 AM
this will help Because your "test1/test2" is already a string literal, Path.Combine will not change the '/' for you to a '\'. Path.Combine will only concat the 2 string literals with the appropriate path delimiter used by the OS, in this case Windows, which is '\', from there your output code :
test1/test2\test3\test4
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Replace all forward slashes that are in paths, with backslash (so, not all forward slashes)
By : user2393776
Date : March 29 2020, 07:55 AM
around this issue I have a file, with file paths such as the following , You can do in-place file edit, code :
perl -pe 's!(c:\S+)! ($x=$1) =~ y|/|\\|; $x !egi'
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Angular route - how to use forward slashes in routing path
By : Sumesh
Date : March 29 2020, 07:55 AM
it fixes the issue How do I use a path with forward slashes in an Angular route? , Use property binding [] instead of interpolation {{}} in your HTML: code :
<a [routerLink]="['/detail', hero.path]">
{{hero.path}}
</a>
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How to forward data packets through an alternative path via an alternative parent?
By : learning
Date : March 29 2020, 07:55 AM
I wish this help you What you want to do is to blacklist a specific parent (or multiple parents). To achieve that, you can add a new field uint8_t is_suspicious to the struct rpl_parent. I assume that you have the logic for setting this flags already in place. Then, when doing the parent selection in RPL (the best_parent function in rpl-dag.c) you can look at the flag and exclude parents that have it set. code :
/* Exclude parents from other DAGs or announcing an infinite rank */
if(p->dag != dag || p->rank == INFINITE_RANK || p->rank < ROOT_RANK(dag->instance)) {
if(p->rank < ROOT_RANK(dag->instance)) {
PRINTF("RPL: Parent has invalid rank\n");
}
continue;
}
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Path with backslashes to path with forward slashes javascript
By : Mac Moraniec
Date : March 29 2020, 07:55 AM
it should still fix some issue The replace method does not alter the current instance of the string, but returns a new one. See if this works:
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