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Is there a DRY(er) way to add items to an array?


Is there a DRY(er) way to add items to an array?

By : Som Aditya
Date : November 22 2020, 10:38 AM
will help you If you really ended up having a lot of that sort of code, you could write a helper function:
code :
function pushIf(array) {
  for (var i = 1; i < arguments.length; i += 2)
    if (arguments[i]) array.push(arguments[i + 1]);
}
pushIf(thingsLeft,
  !$scope.post.title, " Title ",
  !$scope.photo, " Cover Image ",
  !$scope.post.body, " Body",
  !$scope.post.truncBody, " Summary"
);


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iphone: select and copy subset of items from a master array of dictionary items into a temporary array of dictionaries

iphone: select and copy subset of items from a master array of dictionary items into a temporary array of dictionaries


By : user3872372
Date : March 29 2020, 07:55 AM
like below fixes the issue I have an array of dictionary items containing a list of menus and their country of origin. Any number of menus may come from any country. I need an efficient way to select a country and then extract all the items from the first array of dictionaries that pertain to that country. I'm wanting to create a temporary array of dictionaries that contain all the menu and related data for the chosen country.
code :
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"country == %@", @"Italy"];
NSArray *result = [sourceArray filteredArrayUsingPredicate:predicate];
Is it efficient to Remove items from array OR Create new array for remaining items ( Javascript )

Is it efficient to Remove items from array OR Create new array for remaining items ( Javascript )


By : Henrique Matos
Date : March 29 2020, 07:55 AM
help you fix your problem I would guess creating an array is faster in your scenario. The removeAttribute() function should be slower since you have a while loop and then you call Array.splice() (which in the mozilla implementation has 200+ lines of code). Array splice does not only manipulate the existing array, but also returns a new array containing the deleted elements.
However, I agree with T.J Crowder comment that the only correct approach is to measure the efficiency using profilers. To prove my assumptions are right, here is a quick jsperf.com test:
How to remove array items in array 2 if the items doesnt match with items of array 1 and concat with array 3

How to remove array items in array 2 if the items doesnt match with items of array 1 and concat with array 3


By : AbacusMan
Date : March 29 2020, 07:55 AM
To fix this issue I have two arrays: , Here solution:
code :
project_admins=project_users.filter(function(val){ 

  return admin_users.find( function(val2){ 
    return val.username===val2.username 
  });

});
C Program: A array containts items ID's, B array contains sold items find C array which contains unsold items

C Program: A array containts items ID's, B array contains sold items find C array which contains unsold items


By : Ashu kumar
Date : March 29 2020, 07:55 AM
Any of those help This is my program but doesn't work as it is incomplete. , I think you like to find this:
code :
#include <iostream>
using namespace std;

int main(){

int a[]={101,102,103,104,107,110};
int n = sizeof(a) / sizeof(int);

int b[]={102,103,101};
int m = sizeof(b) / sizeof(int);

int c[20];
static int k=0;
int flag;
for(int i =0;i<n;i++){

    int f=0;
    for(int j=0;j<m;j++)
    {                          
        if(a[i]==b[j])
        {
            f=1;
        }

    }
    if(f==0)
    {
        c[k]=a[i];
        printf("c[%d]=%d\n",k,c[k]);
        k++;
    }
}
return 0;
}
c[0]=104
c[1]=107
c[2]=110
Create a function that returns an array with unique items built from two arrays or an array and multiple single items

Create a function that returns an array with unique items built from two arrays or an array and multiple single items


By : user3507754
Date : March 29 2020, 07:55 AM
around this issue Use Array#flat to flatten a single level of the array if it exists (this will leave the already-flat args flattened):
code :
const getDedupedArray = (arr, ...args) => [...new Set([...arr, ...args.flat()])];

console.log(getDedupedArray([1,2], 1, 4));
console.log(getDedupedArray([1,2], [1,4]));
const getDedupedArray = (arr, ...args) => [...new Set(arr.concat(...args))];

console.log(getDedupedArray([1,2], 1, 4));
console.log(getDedupedArray([1,2], [1,4]));
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