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What does int() function with 2 args do in Python


What does int() function with 2 args do in Python

By : Illa Batra
Date : November 22 2020, 10:38 AM
wish helps you The second argument tells int the base of the input string. From the help:
code :
class int(object)
 |  int(x=0) -> integer
 |  int(x, base=10) -> integer
 |  
 |  Convert a number or string to an integer, or return 0 if no arguments
 |  are given.  If x is a number, return x.__int__().  For floating point
 |  numbers, this truncates towards zero.
 |  
 |  If x is not a number or if base is given, then x must be a string,
 |  bytes, or bytearray instance representing an integer literal in the
 |  given base.  The literal can be preceded by '+' or '-' and be surrounded
 |  by whitespace.  The base defaults to 10.  Valid bases are 0 and 2-36.
 |  Base 0 means to interpret the base from the string as an integer literal.
In [63]: int('10', 2)
Out[63]: 2

In [64]: int('10', 3)
Out[64]: 3
In [65]: int("A", 11)
Out[65]: 10


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Python: some function for args -> *args (similar like those in functools)

Python: some function for args -> *args (similar like those in functools)


By : user2482447
Date : March 29 2020, 07:55 AM
hop of those help? You could do this with itertools.starmap or itertools.imap. imap is like starmap except that it zips the arguments first. So instead of calling izip yourself, you could just use imap:
code :
import itertools as it
def vecAdd(v1, v2): return tuple(it.imap(add, v1, v2))
def vecMul(v1, f): return tuple(it.imap(mul, v1, it.repeat(f)))
How to pass a function and its arguments through a wrapper function in R? Similar to *args and *kwargs in python

How to pass a function and its arguments through a wrapper function in R? Similar to *args and *kwargs in python


By : user291540
Date : March 29 2020, 07:55 AM
Hope that helps I want to write a wrapper function in R. I should take a function and its arguments. Do something, and then call the function with the supplied arguments.
code :
wrapper <- function(func, ...) {
    func(...)
}
Threading in Python : Python 'args' is an invalid keyword argument for this function, why?

Threading in Python : Python 'args' is an invalid keyword argument for this function, why?


By : user3860144
Date : March 29 2020, 07:55 AM
it should still fix some issue I think (edited: I'm sure) you have model with name Thread. So you try to instantiate Uzvy.models.Thread, not threading.Thread
Defining function in Python accepts (x, *args), but not (*args, x). Why?

Defining function in Python accepts (x, *args), but not (*args, x). Why?


By : Carlos Gabriel Rodri
Date : March 29 2020, 07:55 AM
hop of those help? *args must be at the end of a function call. This is because if there are arguments after *args, Python has no way of knowing when *args ends and the rest of the arguments begin. If there are a set number of arguments at the start, then *args, it knows to stop at the end of the function.
Python is an interpreted language, so it will read the function from left to right and assign variables as it goes. Take the following:
code :
def foo(bar, *args):
    print("Hello, world!", bar, args)
def foo(*args, bar):
    print("Hello, world!", bar, args)
Passing all elements of tuple in function 1 (from *args) into function 2 (as *args) in python

Passing all elements of tuple in function 1 (from *args) into function 2 (as *args) in python


By : Jessica Bobrowski
Date : March 29 2020, 07:55 AM
this one helps. You "unpack them" with *args. Then the receiving function can mop them up into a tuple again (or not!).
These examples should enlighten things:
code :
>>> def foo(*f_args):
...     print('foo', type(f_args), len(f_args), f_args)
...     bar(*f_args)
...     
>>> def bar(*b_args):
...     print('bar', type(b_args), len(b_args), b_args)
...     
>>> foo('a', 'b', 'c')
('foo', <type 'tuple'>, 3, ('a', 'b', 'c'))
('bar', <type 'tuple'>, 3, ('a', 'b', 'c'))
>>> def bar(arg1, arg2, arg3):
...     print('bar redefined', arg1, arg2, arg3)
...     
>>> foo('a', 'b', 'c')
('foo', <type 'tuple'>, 3, ('a', 'b', 'c'))
('bar redefined', 'a', 'b', 'c')
>>> foo('a', 'b')
('foo', <type 'tuple'>, 2, ('a', 'b'))
---> TypeError: bar() takes exactly 3 arguments (2 given)
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