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C++ finding the (largest) index of the largest element in an array


C++ finding the (largest) index of the largest element in an array

By : user2955178
Date : November 22 2020, 10:38 AM
I wish this helpful for you I have an array of values and a technique for finding the index of the largest element in an array. , In a for loop add an if statement. Something like...
code :
int indexToReturn = 0;
int indexValue = 0;
int newValue = 0;
for (int i = 0; i < arrayCount; i++) {
    newValue = arrayOfValues[i];
    if (newValue >= indexValue) {
        indexToReturn = i;
        indexValue = newValue;
    }
// At the end of this loop the value you want is indexToReturn
}


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Finding the value and index of the first occurence of the largest element in an array

Finding the value and index of the first occurence of the largest element in an array


By : WB130
Date : March 29 2020, 07:55 AM
it helps some times I'm looking for a way to find the value and index of the first occurrence of the largest element in an array (in ruby). I have not been able to find a way to achieve this with fewer than 2 lines of code and without traversing the array more than I would like. ,
I'm more interested in performance
code :
              user     system      total        real
Yours     0.484000   0.000000   0.484000 (  0.485868)
Cary's   36.094000   0.000000  36.094000 ( 36.412679)
require 'benchmark'

example = (1..10**8).to_a
Benchmark.bm(7) do |x|
  x.report("Yours") {
    value = example.max
    index = example.index(value)
  }
  x.report("Cary's") {
    value, index = example.each_with_index.max_by { |n,i| [n,-i] }
  }
end
value, index = example[0], 0
i = 0
example.each do |v|
  if v > value
    value = v
    index = i
  end
  i += 1
end
index = example.index(value = example.max)
Finding index of largest negative and smallest positive element in array

Finding index of largest negative and smallest positive element in array


By : user605509
Date : March 29 2020, 07:55 AM
This might help you I have an array as follows: , You can try, for max of negative:
code :
list(Arr).index(max(Arr[Arr<0]))
list(Arr).index(min(Arr[Arr>0]))
C program to output the largest element of array with the index of the largest element of array

C program to output the largest element of array with the index of the largest element of array


By : rlelis
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Your approach to find the max element in an array is fine. But it alters the original array. If it okay with you, then go ahead with it, else if you would like to keep the array in tact as well as find the max element with the index, then check the code which I have attached below. If you intend to keep the methodology same, then just add a variable, which you should update as and when you find a higher number, as follows:
code :
int max_index;       //declare before
if (arr[0] < arr[i]) {
     max_index  = i;
     arr[0] = arr[i];
}
#include<stdio.h>
int main()
{
int i, max_index;
float arr[5], max;

printf("Please enter five numbers:\n ");

for (i = 0; i < 5; ++i)
{

    scanf("%f", &arr[i]);
}
max  = arr[0];//start off assuming that the 1st element is the max
for (i = 0; i < 5; i++)//now compare it with the rest of the array, updataing the max all along
{
    if (arr[i] > max) {
        max = arr[i];
        max_index = i;
    }
}
printf("Largest element = %.2f at index %d", max, max_index);

return 0;
}
find the index of largest, 2nd largest or third largest in a row of multidimensional array pyhton

find the index of largest, 2nd largest or third largest in a row of multidimensional array pyhton


By : Etim Mkpanam
Date : March 29 2020, 07:55 AM
Any of those help Let say I have the following two numpy arrays: , Here's one that scales well for generic ndarrays -
code :
def maxindex(a, b, fillna=-1):
    sidx = a.argsort(-1)
    m = np.isin(sidx,b)
    idx = m.shape[-1] - m[...,::-1].argmax(-1) - 1
    out = np.take_along_axis(sidx,idx[...,None],axis=-1).squeeze()
    return np.where(m.any(-1), out, fillna)
In [83]: a
Out[83]: 
array([[ 1,  4,  6,  2,  5],
       [ 3,  2,  7, 12,  1],
       [ 8,  5,  3,  1,  4],
       [ 6, 10,  2,  4,  9]])

In [84]: b
Out[84]: array([0, 1, 4])

In [85]: maxindex(a, b) # all rows
Out[85]: array([4, 0, 0, 1])

In [86]: maxindex(a[1], b) # second row
Out[86]: array([0])
In [105]: a
Out[105]: 
array([[[ 1,  4,  6,  2,  5],
        [ 3,  2,  7, 12,  1],
        [ 8,  5,  3,  1,  4],
        [ 6, 10,  2,  4,  9]],

       [[ 1,  4,  6,  2,  5],
        [ 3,  2,  7, 12,  1],
        [ 8,  5,  3,  1,  4],
        [ 6, 10,  2,  4,  9]]])

In [106]: maxindex(a, b)
Out[106]: 
array([[4, 0, 0, 1],
       [4, 0, 0, 1]])
finding the index of the largest element in an array

finding the index of the largest element in an array


By : Pierre Taquet
Date : March 29 2020, 07:55 AM
will be helpful for those in need I want to write a code that returns the index of the largest element in a given array. However, when I try compiling, I get a message that I can't seem to understand. Although I have done the things that the error message tells, it keeps telling me to fix them. Please help this novice programmer! , This type of initialization can't be done outside of a method :
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