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How can I check if a list exist in a dictionary of lists in the same order


How can I check if a list exist in a dictionary of lists in the same order

By : Brittany Reid
Date : November 22 2020, 10:38 AM
will be helpful for those in need Say I have a dictionary of lists, , Use any for a list of lists:
code :
d = {1 : [1,2,3], 2: [2,1]}
lsts = [[1,2],[2,1]]
print(any(x in d.values() for x in lsts))
True

d = {1:[1,2,3],2:[1,2]}
lsts = [[3,2,1],[2,1]]
print(any(x in d.values() for x in lsts))
False
lst = [1,2]
lst in d.itervalues()


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Radio Button List, Check Boxes, Drop Down Lists and Enums/Dictionary Lists

Radio Button List, Check Boxes, Drop Down Lists and Enums/Dictionary Lists


By : ahmed amz
Date : March 29 2020, 07:55 AM
Does that help Try using MVCGrabBag. It has a common code base for all the inputs. It uses enums and a bit of a different style in terms of getting it to work. But once you get your head wrapped around the basics you will not be disappointed. All you do is do a @Html.FullFieldEditor and it takes care of the rest with code. There is basically a Selector.cs and some other files that figure out, much like the @Html.EditorFor helper does, what input to create. And instead of using a bunch of /EditorTemplates/ it just has one that takes care of everything.
It appears to be fairly new, so I trust it will gain momentum. I have to imagine for those of us non-superhuman coders out there that this would alleviate the problem of not having any uniform structure to something that has been around since the dawn of the web (I'm talking inputs).
Create dictionary from list of lists. Append items to dictionary value if key exist

Create dictionary from list of lists. Append items to dictionary value if key exist


By : Andrew Zalevsky
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You could use collections.defaultdict:
code :
>>> from collections import defaultdict
>>> d = defaultdict(list)
>>> for key in sorted(My_dict):
...     d[My_dict[key][0]].extend(My_dict[key][1:])
... 
>>> 
>>> dict(d)
{'Name1': ['value1', 'value2', 'value3', 'value7', 'value8', 'value9'], 'Name2': ['value4', 'value5', 'value6']}
>>> d = defaultdict(set);
>>> for value in My_dict.values():
...     d[value[0]] |= set(value[1:])
...
>>> dict(d)
{'Name1': {'value8', 'value3', 'value2', 'value1', 'value7', 'value9'}, 'Name2': {'value4', 'value5', 'value6'}}
Check lists of objects for equality without order check in their List property

Check lists of objects for equality without order check in their List property


By : Nirav
Date : March 29 2020, 07:55 AM
will be helpful for those in need If order does not matter for your attributes and they are unique (i.e. may not have multiple attributes of the same type) you might change the structure into a Set instead and just use the regular compare.
If you want to preserve order but compare (unique) attributes you may convert them to set when comparing, see Easiest way to convert a List to a Set in Java.
how to check if a positional element in a list of lists does not exist in another list of lists

how to check if a positional element in a list of lists does not exist in another list of lists


By : Roussel Rojas
Date : March 29 2020, 07:55 AM
this one helps. Create a set of all third elements from the first list, then test your tuples from the second list against the set:
code :
third_positions = {t[2] for t in list1}
[t for t in list2 if t[2] not in third_positions]
>>> list1 = [('1', '2', '3'), ('a', 'b', 'c'), ('4', '5', '6')]
>>> list2 = [('a', 'b', 'c'), ('m', 'n', 'b'), ('p', 'q', '6')]
>>> third_positions = {t[2] for t in list1}
>>> print([t for t in list2 if t[2] not in third_positions])
[('m', 'n', 'b')]
[t for t in list2 if not any (t[2] == u[2] for u in list1)]
Sort a dictionary by list of lists in increasing order

Sort a dictionary by list of lists in increasing order


By : Apoorva Chourey
Date : March 29 2020, 07:55 AM
With these it helps It looks like you are trying to sort by the length of the list in the dictionary. This is how you would do that:
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