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DATEDIFF Current/Date for Last Record


DATEDIFF Current/Date for Last Record

By : Calcula Thor
Date : November 22 2020, 10:38 AM
may help you . you can use group by to get only 1 row per doctor and max to select latest date:
code :
select `Doctor`, DATEDIFF(CURDATE(),max(`Date`))
from `Report`
group by `Doctor`


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DateDiff vbscript to find current date files

DateDiff vbscript to find current date files


By : Kabelo
Date : March 29 2020, 07:55 AM
With these it helps When you create a datetime value without a time portion in VBScript, the time is automatically assumed to be 00:00:00 (see for instance the return value of TimeValue(Date)). Because of this DateDiff() compares the "last modified" timestamp of the file with the current date at 00:00:00 and returns a value greater than 1 (or less than -1) when the difference exceeds ±24 hours.
For comparing just the date parts of two timestamps use the FormatDateTime() function:
code :
today = FormatDateTime(Date, vbShortDate)
If FormatDateTime(RFile.DateLastModified, vbShortDate) = today Then
  '...
End If
Trying to get Date/Time from earlier record which meets certain criteria compared to current record, in order to calcula

Trying to get Date/Time from earlier record which meets certain criteria compared to current record, in order to calcula


By : Nicholas Knize
Date : March 29 2020, 07:55 AM
around this issue This will provide the prior time and you can do the difference calc from here (I named the data table "sample"):
code :
SELECT Sample.userid, Sample.Customer, Sample.Food, Sample.DateTime, Sample.Activity, IIf([sample].[activity]="Trash",(select max(DateTime) from sample S where (s.userid=sample.userid and s.customer=sample.customer and s.food=sample.food and s.datetime<=sample.datetime and s.activity="serve"))) AS [Prior]
FROM Sample
ORDER BY Sample.userid, Sample.Customer, Sample.Food, Sample.DateTime, Sample.Activity;
userid  Customer    Food    DateTime    Activity    Prior
Server1 Cust1   Burger  12/20/2014 1:19:08 AM   Serve   
Server1 Cust1   Burger  12/20/2014 1:19:12 AM   Trash   12/20/2014 1:19:08 AM
Server1 Cust1   Burger  12/20/2014 6:20:11 AM   Serve   
Server1 Cust1   Burger  12/20/2014 6:20:11 AM   Trash   12/20/2014 6:20:11 AM
Server1 cust2   Burger  11/8/2014 2:31:09 AM    Serve   
Server1 cust2   Burger  11/8/2014 2:31:09 AM    Trash   11/8/2014 2:31:09 AM
Server1 cust2   Burger  11/8/2014 2:32:59 AM    Trash   11/8/2014 2:31:09 AM
Server1 cust2   Burger  11/8/2014 7:09:14 AM    Serve   
Server1 cust2   Burger  11/8/2014 7:09:22 AM    Trash   11/8/2014 7:09:14 AM
Server2 Cust3   Fries   12/20/2014 6:33:44 PM   Serve   
Server2 Cust3   Fries   12/20/2014 6:33:44 PM   Trash   12/20/2014 6:33:44 PM
Server2 Cust3   Fries   12/20/2014 10:24:13 PM  Serve   
Server2 Cust3   Fries   12/20/2014 10:24:13 PM  Trash   12/20/2014 10:24:13 PM
Server2 Cust3   Fries   12/20/2014 10:25:00 PM  Trash   12/20/2014 10:24:13 PM
Server2 Cust4   Fries   3/31/2014 10:48:48 PM   Serve   
Server2 Cust4   Fries   3/31/2014 10:48:49 PM   Serve   
Server2 Cust4   Fries   3/31/2014 10:48:49 PM   Trash   3/31/2014 10:48:49 PM
DateDiff use current date if enddate is null

DateDiff use current date if enddate is null


By : Zak Karst
Date : March 29 2020, 07:55 AM
this one helps. I am calculating two dates and returning days but want to exclude weekends and holidays. I also want to say, if the enddate is null, then use the current date? , Or use this..
code :
if object_id('tempdb..#Holidays') is not null drop table temp..#Holidays
create table #Holidays(id int identity(1,1),Holiday date)
insert into #Holidays values ('2015-12-25'),('2015-12-28')
set dateformat ymd
declare @StartDate date = '2015-12-01'
declare @EndtDate date = '2015-12-31'
--some times @EndtDate might be NULL so, set to getdate()
set @EndtDate = isnull(@EndtDate,cast(getdate() as date))

declare @Holiday int 
set @Holiday = (select count(*) from #Holidays where Holiday between @StartDate and @EndtDate)

SELECT
   (DATEDIFF(dd, @StartDate, @EndtDate) + 1)
  -(DATEDIFF(wk, @StartDate, @EndtDate) * 2)
  -(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, @EndtDate) = 'Saturday' THEN 1 ELSE 0 END)
  -@Holiday
How to put current date in to my SQL datediff

How to put current date in to my SQL datediff


By : user2165203
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Assuming your due date column is called date, then your query should be
code :
$sql = "SELECT id, due, DATEDIFF(date, CURDATE()) AS paydate FROM sales WHERE due != '0' ";
$paydate =  $row ["datediff(pay_date, date)"]
$paydate = $row['paydate'];
Datediff function between a date column and current date?

Datediff function between a date column and current date?


By : user3588908
Date : March 29 2020, 07:55 AM
Does that help In SQL SERVER, you can use the following query (replace the date with your field):
code :
SELECT CASE WHEN datediff(year, '20120303', getdate()) > 1 
   THEN datediff(year, '20120303', getdate()) 
   ELSE datediff(day, '20120303', getdate()) END AS Diff
SELECT CASE WHEN datediff(year, date_column, getdate()) > 1 
   THEN datediff(year, date_column, getdate()) 
   ELSE datediff(day, date_column, getdate()) END AS Diff
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