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Is there any benefit to using Math.Floor over explicit integer casting?


Is there any benefit to using Math.Floor over explicit integer casting?

By : user2955101
Date : November 22 2020, 10:38 AM
seems to work fine Yes, for negative numbers, this works in the opposite way.
Example (using Mono's C# interactive shell csharp):
code :
csharp> Math.Floor(-12.0d)
-12
csharp> Math.Floor(-12.5d) 
-13
csharp> (int) -12.5
-12
csharp> double ac = 1.023e23;
csharp> Math.Floor(ac);
1.023E+23
csharp> (int) ac;
0
System.out.println(Math.floor(Double.POSITIVE_INFINITY)); // Prints Infinity
System.out.println((int)Double.POSITIVE_INFINITY);        // Prints 2147483647
System.out.println(Math.floor(Double.NaN));               // Prints NaN
System.out.println((int)Double.NaN);                      // Prints 0


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C++ Type Casting: benefit of using explicit casts?

C++ Type Casting: benefit of using explicit casts?


By : user2087987
Date : March 29 2020, 07:55 AM
wish help you to fix your issue From the list of casts you provided, the only one that makes sense to be used to supstitute an implicit cast is the static_cast.
dynamic_cast is used to downcast a superclass into its subclass. This cannot happen implicitly and is actually something that is not that rare in OOP. static_cast could be used in such a cast too, it is however more dangerous, as it does not check during run time that the downcast is valid.
Why is Math.floor() used instead of integer division in BER Codec

Why is Math.floor() used instead of integer division in BER Codec


By : Jan Geheim moinmoin0
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further To answer the technical part of your question:
Using math.floor() is superfluous: temp / 256 is an integer (by Java's rules for integer arithmetic), and using Math.floor() on an integer is pointless. You could simply use temp / 256.
math.floor is supposed to return integer

math.floor is supposed to return integer


By : Anna
Date : March 29 2020, 07:55 AM
With these it helps "Math.Floor is supposed to take a decimal or double and return an integer." No, it isn't. It returns a value of the same type as its argument. See the documentation, e.g. Math.Floor Method (Double).
I would have expected VS to suggest a fix of adding CInt() around the RHS of the assignment; did that not appear for you?
floor() and ceil() functions vs casting to integer in C

floor() and ceil() functions vs casting to integer in C


By : Shervinooo
Date : March 29 2020, 07:55 AM
this will help The functions ceil() and floor() will return different numbers than what you get by using
code :
up = (int)(test + 1);
down  = (int)test;
float test = -1.3548;
up = (int)test;        // ceil()
down = (int)(test-1);  // floor()
Why isn't explicit type casting for Math.pow() causing integer overflow?

Why isn't explicit type casting for Math.pow() causing integer overflow?


By : user2378713
Date : March 29 2020, 07:55 AM
This might help you If a double is larger than the maximal int value, converting it to int will give you the maximal int value.
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