'template argument deduction/substitution failed' after addition of an argument

'template argument deduction/substitution failed' after addition of an argument

By : sdev
Date : November 22 2020, 10:33 AM
This might help you Since clang++ shows a different (and strange) behaviour in this case, I'm not entirely sure of this answer. However, I think I can explain what's going on when using g++.
Let's take a look at the following example:
code :
#include <iostream>

template<typename ...ARGS1, typename ...ARGS2>
void foo(void (*)(ARGS1..., ARGS2...))
    std::cout << __PRETTY_FUNCTION__ << "\n";

void bar(int, bool, double, void*, float) {}

int main() {
void foo(void (*)(ARGS1 ..., ARGS2 ...))
[with ARGS1 = {}; ARGS2 = {int, bool, double, void*, float}]
template<typename T>
void foo(T, T) {}

foo(1, 2.3)
template<typename... T>
void foo(tuple<T...>, tuple<T...>) {}

foo(tuple<int, double>{}, tuple<bool, char>{})
template<typename ...ARGS1, typename ...ARGS2>
void foo(void (*)(ARGS1..., ARGS2...))
template<typename ...ARGS1, typename ...ARGS2>
void foo(void (*)(ARGS1..., ARGS2...), tuple<ARGS2...>)
void bar(int, double);
tuple<int, double> t;
foo(&bar, t); // works

tuple<double> u;
foo(&bar, u) // fails: inconsistent deduction results.
template<typename T>
struct identity_t
{ using type = T; };

template<typename T>
using non_deduced_context = typename identity_t<T>::type;

template<typename ...ARGS1, typename ...ARGS2>
void foo(const std::tuple<ARGS1...> &, const std::tuple<ARGS2...> &,
         non_deduced_context<void (*)(ARGS1..., ARGS2...)>)
    //call function
template<typename F>
void foo(F f)
    //call function, e.g.

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template argument deduction/substitution failed

template argument deduction/substitution failed

By : Denny Semplicemente
Date : March 29 2020, 07:55 AM
wish of those help I want to implement a container which can accept initial list of elements by supplying the constructor with sequence of values. , In the declaration
code :
template <class T>
c_array(typename T::iterator begin,typename T::iterator end)
template <class InputIter>
c_array(InputIter begin, InputIter end) {
    std::copy_n(begin, max, v);
C++ - Template argument deduction/substitution failed

C++ - Template argument deduction/substitution failed

By : Mason Banks
Date : March 29 2020, 07:55 AM
will help you You can accomplish this with the use of common type
code :
#include <vector>
#include <type_traits>

using namespace std;

template <class S, class T> 
vector<typename std::common_type<S, T>::type> operator+(const vector<S> &a, const vector<T> &b)
    vector<typename std::common_type<S, T>::type> result;
    for(unsigned int i = 0; i < a.size();++i){
        result[i] = a[i] + b[i];
    return result;

int main() {
    vector<double> bla;
    bla = bla + bla;
    return 0;
Template argument deduction/substitution failed, when using typename argument

Template argument deduction/substitution failed, when using typename argument

By : user147734
Date : March 29 2020, 07:55 AM
I hope this helps you . The reason that the C++ compiler can't figure this out has to do with template specialization. For example, suppose that you specialize the W struct template like this:
code :
template <> struct W<137> {
    using T = Y<0>; // Not Y<137>
template argument deduction/substitution failed: is there no first, second for map?

template argument deduction/substitution failed: is there no first, second for map?

By : Kahekshan Parveen
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You can't use std::sort() to sort a std::map.
As you can see, in this page, the requirement for std::sort()
template argument deduction/substitution failed. y?

template argument deduction/substitution failed. y?

By : samiam
Date : March 29 2020, 07:55 AM
hop of those help? T in typename enabler::value, T>::type is non-deducible:
§ [temp.deduct.type]/p5:
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