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ValueError: too many values to unpack


ValueError: too many values to unpack

By : user2954898
Date : November 22 2020, 10:33 AM
should help you out I am trying to sort dictionaries in MongoDB. However, I get the value error "too many values to unpack" because I think it's implying that there are too many values in each dictionary (there are 16 values in each one). This is my code: , You pass the arguments and values in unpacked as so:
code :
FortyMinute.find().sort('Rank', 1)
FortyMinute.find().sort([(Rank', 1), ('Date', 1)])
FortyMinute.find().sort('Rank',pymongo.DESCENDING)
sorted(FortyMinute.find(), key=key_function)


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ValueError: too many values to unpack, while trying to unpack a simple.txt file

ValueError: too many values to unpack, while trying to unpack a simple.txt file


By : Raffaele
Date : March 29 2020, 07:55 AM
With these it helps You're trying to unpack four columns into three variables -- the Exponential_sum variable is missing!
ValueError: too many values to unpack 3

ValueError: too many values to unpack 3


By : Karen McCandies
Date : March 29 2020, 07:55 AM
will help you The shape of X is (32, 3), but in your list comprehension, you are only trying to unpack 2 values:
code :
Y = [[int(x0+x1<1)] for (x0,x1) in X]
X = rng.rand(32,2)
Y = [[int(x0+x1<1)] for (x0,x1, _) in X]
how to fix ValueError: too many values to unpack

how to fix ValueError: too many values to unpack


By : user2618480
Date : March 29 2020, 07:55 AM
I hope this helps . An odict_iterator (what you get when using an OrderedDict in a for loop like this) only yields its keys, not the key/value pairs. Use the items method to get those:
code :
for name, language in languages.items():
    ...
Unpack value(s) into variable(s) or None (ValueError: not enough values to unpack)

Unpack value(s) into variable(s) or None (ValueError: not enough values to unpack)


By : ignacho
Date : March 29 2020, 07:55 AM
should help you out Use the * operator and fill an intermediate iterable with that which you're unpacking and fill the remainder with your default value of choice.
code :
x = [1, 2]
defaultValue = None
one, two, three = [*x, *([defaultValue] * (3 - len(x)))]
def unpack(source, target, defaultValue=None):
    n = len(source)
    if n < target:
        return [*source, *([defaultValue] * (target - len(source)))]
    elif n > target:
        return source[0:target]
    else:
        return source
ValueError: not enough values to unpack (expected 2, got 1) when trying to unpack dict in python for data labeling with

ValueError: not enough values to unpack (expected 2, got 1) when trying to unpack dict in python for data labeling with


By : user3694262
Date : March 29 2020, 07:55 AM
should help you out I created a dictionary that label each api endpoint from my backend to a product group. Currently I'm trying in python 3.7.6 to use this dictionary to further label all data in the csv that I get from NewRelic with data from all transactions (avg latency, request count, etc.). The code is teh following: , Replace your code:
code :
for k, v in doc_dic:
        if k == resp.Action:
            resp.insert(0, "Product Group", v)
for k, v in doc_dic.items():
        if k == resp.Action:
            resp.insert(0, "Product Group", v)
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