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jquery: filter using AND OR in selector


jquery: filter using AND OR in selector

By : Syn
Date : November 22 2020, 10:33 AM
it helps some times There's probably a more elegant solutions, but if I understand correctly, concatenating in one single selector will match all of them (as the current behavior).
I created a new fiddle for you to see, basically I filter for each type with only the results other filters.
code :
$lis.hide();
$lis = filter($lis, 'color');
$lis = filter($lis, 'size');
$lis = filter($lis, 'continent');
$lis.show();


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jQuery filter selector, is this right?

jQuery filter selector, is this right?


By : user2037127
Date : March 29 2020, 07:55 AM
this one helps. It seems to work ok but I don't know if this can be impoved on or not.
code :
jQuery(document).ready(function(){ 
jQuery('body *') 
.filter(function() { 
    return this.className.match(/edit-(text|html)-\d/); 
}) 
.css({ 
    'color': '#ff0000' 
}); 
How to use jQuery selector to filter jQuery isotope items case-insensitive (search)

How to use jQuery selector to filter jQuery isotope items case-insensitive (search)


By : Shantanu Gangal
Date : March 29 2020, 07:55 AM
this will help use lower case as protocol for all attributes and then change user input to lowercase
jquery filter selector vs filter method

jquery filter selector vs filter method


By : Thomas Bazzucchi
Date : March 29 2020, 07:55 AM
it helps some times I'm having an issue with getting the jquery filter method to work. , In your first version:
code :
$('#resultDiv').find("tr:odd").addClass("alternate_row");
$('#resultDiv tr').filter(":odd").addClass("alternate_row");
jQuery filter /selector

jQuery filter /selector


By : Halcu Ionela
Date : March 29 2020, 07:55 AM
wish of those help try this . you have missed - in between first and child. this is to access direct child
code :
 $('span.one > a:first-child')
 $('span.one a:first-child')
Jquery Selector using eq() with filter()

Jquery Selector using eq() with filter()


By : Tat1ana
Date : March 29 2020, 07:55 AM
around this issue
I ended up using .find() instead of .filter(), but I think it would be more appropriate to use .filter().
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