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Pass JSON data to strongly typed partial view in ASP.NET


Pass JSON data to strongly typed partial view in ASP.NET

By : Brett Hyland
Date : November 22 2020, 10:33 AM
I wish this help you You are trying to inject client-side code into the server-side generation of the partial view. That is not the way MVC partial views work. The partial view is already rendered before the page is supplied to the browser (i.e. long before the client side jQuery is run).
Instead you need to POST/GET the data to a controller method, return your partial view based on that data, and then render the returned HTML by inserting it into your page.
code :
function showPartial(data) {
    $.ajax({
       url: "controller/action",
       data: data,
       dataType: html,    // Expect back HTML
       success: function(html){
           $('#someelement').html(html);
       }
    });
}
function showPartial(data) {
    $('#someelement').load( "controller/action", data );
}


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Pass Additional ViewData to a Strongly-Typed Partial View

Pass Additional ViewData to a Strongly-Typed Partial View


By : dimitraros
Date : March 29 2020, 07:55 AM
I wish this helpful for you RenderPartial takes another parameter that is simply a ViewDataDictionary. You're almost there, just call it like this:
code :
Html.RenderPartial(
      "ProductImageForm", 
       image, 
       new ViewDataDictionary { { "index", index } }
); 
How can i pass a model to a strongly typed partial view

How can i pass a model to a strongly typed partial view


By : Jack Merhi
Date : March 29 2020, 07:55 AM
hope this fix your issue Assuming that you have no reference it on your view to the model, you can do the following one :
code :
  @{
      var repo = new Models.MyRepo();
      var partialModel = repo.GetAll();
  }

  @Html.Partial("CommentForm", partialModel)
public class MyViewModel { 

    public MyNS.Models.News News {get; set;}
    public MyNS.Models.NewsComment NewsComment {get; set;}

}
var viewModel = new MyViewModel();
viewModel.News = repo.GetNews();
viewModel.NewsComment = repo.GetNewsComment();

retun View(viewModel);
@Html.Partial("CommentForm", Model.NewsComment)
.NET MVC 4 Strongly typed ViewModel containing Strongly typed Model with EditorFor and EditorTemplate partial view not b

.NET MVC 4 Strongly typed ViewModel containing Strongly typed Model with EditorFor and EditorTemplate partial view not b


By : demo
Date : March 29 2020, 07:55 AM
I wish did fix the issue. This was a simple issue, if someone else comes across it maybe this will help them. I didn't have the properties on the class declared as properties with get; set;
code :
public class RolePermission {

public int id { get; set; } 

public bool permission_value { get; set; } 

public string name { get; set; } 

}
using strongly typed partial views inside another Strongly Typed view

using strongly typed partial views inside another Strongly Typed view


By : GeoArt
Date : March 29 2020, 07:55 AM
I hope this helps . I have NameModel and RegisterModel and SuperClass classes as below: - , The simplest way to do this is to use a child action
code :
@model MyNamespace.Models.Register.SuperModel
@{
    Layout = "~/Views/_Layout.cshtml";
}



@using (Html.BeginForm(null, null, FormMethod.Post, new { id = "myForm" }))
{
   <div id="form">
       @Html.Action("MyNamePartialView")
   </div>
    @Html.TextBoxFor(m=>m.Register.UserName,new { @id="userName"})
    @Html.TextBoxFor(m=>m.Register.Password,new { @id="password"})
    <input type="submit" value="Register" id="btnRegister" />
}
public ActionResult Register(RegisterModel RegisterInfo, NameModel NameInfo)
Rendering a strongly typed partial view within another strongly typed partial view - incorrect model being passed into c

Rendering a strongly typed partial view within another strongly typed partial view - incorrect model being passed into c


By : Muhammad Inam ul haq
Date : March 29 2020, 07:55 AM
will be helpful for those in need I have re-created your project with the following change in ShoutController:
code :
var shouts = (from s in db.Shouts
                  orderby s.EntryDate descending
                  select s)
                  .Take(20)
                  .ToList();

shouts.Add(new Shout{Author = "T", EntryDate = DateTime.Now, Id = 1, Message = "some message"});
shouts.Add(new Shout { Author = "T2", EntryDate = DateTime.Now, Id = 2, Message = "some message2" });

var shoutboxView = new ShoutboxView
{
    newShout = new Shout(),
    Shouts = shouts
};

return PartialView(shoutboxView);
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