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G-machine, (non-)strict contexts - why case expressions need special treatment


G-machine, (non-)strict contexts - why case expressions need special treatment

By : user2954745
Date : November 22 2020, 10:31 AM
I think the issue was by ths following , The purpose of the C scheme is to not perform any computation, but just delay everything until an EVAL happens (which it might or might not). What are you doing in your proposed code generation for case? You're calling EVAL! And the whole purpose of C is to not call EVAL on anything, so you've now evaluated something prematurely.
The only way you could generate code directly for case in the C scheme would be to add some new instruction to perform the case analysis once it's evaluated.
code :


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What explains the different treatment of special characters in regular expressions?

What explains the different treatment of special characters in regular expressions?


By : user3030304
Date : March 29 2020, 07:55 AM
this will help The escape sequences in regular expressions are not identical to the ones in string literals. In a regular expression, \b matches a word boundary. \t happens to be the same in regular expressions and string literals.
MDC has a fairly good writeup of these, although of course there's nothing like going to the specification.
SHA-512 special character treatment

SHA-512 special character treatment


By : LPSanz
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Is r1 a valid base64 encoded string? It seems to me you're getting the same result because you're trying to decode something which is not a valid Base64 array, and BASE64Decoder is somehow failing silently. Have you tried something like:
code :
byte[] b = r1.getBytes("UTF-8");
MessageDigest md=MessageDigest.getInstance("SHA-512");
md.update(b);
byte[] plaintext=md.digest();
BASE64Encoder encoder=new BASE64Encoder();
String digest1=encoder.encode(plaintext);   //digest1 contains the msg digest
Special case treatment for the last element of a range in Google Go's text templates

Special case treatment for the last element of a range in Google Go's text templates


By : Sandy Adriaenssens
Date : March 29 2020, 07:55 AM
With these it helps See this example from the go-nuts mailing list. One key to this trick is that a template if is different than a Go language if. A template can test for a value of zero, unlike the Go language that requires a boolean. The magic is then {{if $index}},{{end}} where $index needs no declaration other than its appearance in the assignment.
PHP Special treatment on an array

PHP Special treatment on an array


By : Ryan Squiller
Date : March 29 2020, 07:55 AM
I hope this helps . I have this array : , will this do the work for you ?
code :
$string = "location.address.streetNumber";

$firstArray = explode('.', $string);
$secondArray = ['location' => ['address' => ['streetNumber' => 'street 854']]];

$ref = &$secondArray;
foreach($firstArray as $val){
    $ref = &$ref[$val];
}

$value = $ref;
unset($ref);

echo $value // street 854
Split camel case string with number special treatment

Split camel case string with number special treatment


By : JohnYeldham
Date : March 29 2020, 07:55 AM
it should still fix some issue Looks like you want to split before any uppercase letter that is preceded by a lowercase letter, i.e. between a lowercase letter and an uppercase letter, so:
Split using regular expression:         (?<=[a-z])(?=[A-Z])
code :
public static void main(String[] args) {
    test("SomeString");
    test("SomeString1");
    test("SomeString1Word");
}
private static void test(String text) {
    String regex = "(?<=\\p{Ll})(?=\\p{Lu})";
    System.out.printf("%s -> %s%n", text, Arrays.toString(text.split(regex)));
}
SomeString -> [Some, String]
SomeString1 -> [Some, String1]
SomeString1Word -> [Some, String1Word]
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