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Retrieve records from multiple Records returned by Sub-Query


Retrieve records from multiple Records returned by Sub-Query

By : Eedhal Softwares
Date : November 22 2020, 10:31 AM
This might help you You can have access to anything and everything from a subquery if you use it right. The best way to build a complicated query is to start simply, seeing what data you have and usually the answer, or the next step, will be obvious.
So let's start by displaying all the accidents for 2013. We aren't interest in the individual cars, just the most expensive accidents by type. So...
code :
select  c.car_type, f.cost
from    car_acc a
join    cars    c
    on  c.car_id = a.car_id
join    final_cost f
    on  f.car_acc_id = a.car_acc_id
where   f.fittest_date >= date '2013-01-01'
   and  f.fittest_date <  date '2014-01-01';
select  c.car_type, Max( f.cost ) MaxCost
from    car_acc a
join    cars    c
    on  c.car_id = a.car_id
join    final_cost f
    on  f.car_acc_id = a.car_acc_id
where   f.fittest_date >= date '2013-01-01'
   and  f.fittest_date <  date '2014-01-01'
group by c.car_type;
with MaxPerType( car_type, MaxCost )as(
  select  c.car_type, Max( f.cost ) MaxCost
  from    car_acc a
  join    cars    c
      on  c.car_id = a.car_id
  join    final_cost f
      on  f.car_acc_id = a.car_acc_id
  where   f.fittest_date >= date '2013-01-01'
     and  f.fittest_date <  date '2014-01-01'
  group by c.car_type
)
select  m.car_type, m.MaxCost
from    MaxPerType m
where   m.MaxCost =(
     select  Max( MaxCost )
     from    MaxPerType );


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How to write a query to join 2 tables and only return records where MULTIPLE child records are included in a set of poss

How to write a query to join 2 tables and only return records where MULTIPLE child records are included in a set of poss


By : Thusitha Dassanayake
Date : March 29 2020, 07:55 AM
this will help Beside the other solutions, using the Exists() operator is an easy way of doing this type of request, something like:
code :
SELECT p.* FROM person p Where Exists (Select * from interests i where i.person = p.name and i.interest = 'skiing') and Exists (Select * from interests i where i.person = p.name and i.interest = 'biking')
SQL query that will retrieve multiple records when only one meets the criteria

SQL query that will retrieve multiple records when only one meets the criteria


By : Dylan Perks
Date : March 29 2020, 07:55 AM
wish helps you I have a table with multiple records for each account, each record has a unit# with a balance. I want to select the account if one of the units has a negative balance and return all records for that account including the record with the negative unit. for example: Acct # 1234 has two records (each having a different unit# and balance). One unit has a negative balance and one has a positive balance. I want to retrieve both the unit records for any account where one unit is negative. How would I accomplish this? , A simple IN will do it in standard SQL;
code :
SELECT * FROM myTable 
WHERE account_id IN (
    SELECT account_id FROM myTable WHERE balance < 0
)
CloudKit - How to share multiple records and retrieve shared records?

CloudKit - How to share multiple records and retrieve shared records?


By : ahmed
Date : March 29 2020, 07:55 AM
this one helps. I believe Thunk's answer is incorrect, since you should not have to fetch any records with the parent reference to a given record. First, where would you search? The child records of the CKShare root record do not appear in your shared database and you don't have access to the other user's private zone. Luckily, CloudKit will push to you all child records referenced by the CKShare's root record. The following approach will also solve the second problem, you will be notified of any and all future changes automatically!
The key is to simply add a CKDatabaseSubscription to the shared database in the CloudKit container. Let's assume you are the client. Anytime another user share's a record with you, the CKShare record and the underlying root record referenced by the share are both situated in a custom zone in that user's private database. When you accept the share (triggering an application delegate method userDidAcceptCloudKitShareWith), the same CKShare and underlying record are now visible to you, except that they are both visible in your shared database. If you have subscribed to the shared database, the subscription will kick in and notify you right after you accept the share. Now you can fetch all changes in the shared database using CKFetchDatabaseChangesOperation. In the recordZoneWithIDChangedBlock, the CKRecordZoneID of the sharing user's custom zone will be given. You use this to trigger a CKFetchRecordZoneChangesOperation (be sure to perform this operation in the shared database!), which returns the CKShare, the underlying root record, and all records that have a parent reference to the underlying referenced record.
Oracle query - get latest record if multiple records are returned

Oracle query - get latest record if multiple records are returned


By : Jörgen Andersson
Date : March 29 2020, 07:55 AM
this one helps. I am using a stored procedure inside a package that connects to a DB using db link and periodically pulls data to update local DB. It does so by pulling data into a "staging" table, do some processing and update local table. , You can use window functions for that:
code :
select A, B, ITEM_ID, EVENTCODE, CREATEDON from 
    (select A, B, ITEM_ID, EVENTCODE, CREATEDON, 
                   row_number() over(partition by ITEM_ID, EVENTCODE 
                        order by CREATEDON desc) rn from SOME.DBLINK@BLAH
     where STATUS=1 and PCIKEDON is null
    )
where rn = 1;
Dynamically create multiple DataTables based on number of records returned from SQL query in C#?

Dynamically create multiple DataTables based on number of records returned from SQL query in C#?


By : Cherry
Date : March 29 2020, 07:55 AM
should help you out I am querying a database to get a dynamically number of records, let's say I get 11000 records returned. , I haven't tested it but something like this should work.
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