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Sort an array of arrays in Erlang


Sort an array of arrays in Erlang

By : user2954653
Date : November 22 2020, 10:31 AM
Does that help As I said in my comment, the sort function of the lists library does exactly what you want.
code :
1> lists:sort( [ [6,0], [12,1], [5,2], [10,3] ]).
[[5,2],[6,0],[10,3],[12,1]]
2>


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Sort an array of associative arrays by the order of another array where arrays are different lengths

Sort an array of associative arrays by the order of another array where arrays are different lengths


By : Luke StackWalker
Date : March 29 2020, 07:55 AM
it helps some times This is a tricky one to explain.. , try this:
code :
$flipped_categories = array_flip($categories);
array_merge($flipped_categories, $product_array);
Javascript: Sort multi dimensional Array based on first arrays sort results

Javascript: Sort multi dimensional Array based on first arrays sort results


By : A Tong
Date : March 29 2020, 07:55 AM
To fix the issue you can do You could "merge" them into a single object with two properties, sort by the first one, and then separate back in the end (see demo here):
code :
function sortBoth(ary1, ary2) {
    var merged = [];
    for (var i=0; i < ary1.length; i++) merged.push({'ary1': ary1[i], 'ary2': ary2[i]});
    merged.sort(function(o1, o2) { return ((o1.ary1 < o2.ary1) ? -1 : ((o1.ary1 == o2.ary1) ? 0 : 1)); });
    for (var i=0; i < merged.length; i++) { ary1[i] = merged[i].ary1; ary2[i] = merged[i].ary2; }
}

var ary1 = new Array("d", "a", "b", "c");
var ary2 = new Array("ee", "rr", "mm", "yy");

console.log(ary1);
console.log(ary2);

sortBoth(ary1, ary2);

console.log(ary1);
console.log(ary2);
[ "d",  "a",  "b",  "c"]
["ee", "rr", "mm", "yy"]
[ "a",  "b",  "c",  "d"]
["rr", "mm", "yy", "ee"] 
PHP - sort arrays of arrays which are values of an assoc array, by element of lowest level array

PHP - sort arrays of arrays which are values of an assoc array, by element of lowest level array


By : Anime Trackz
Date : March 29 2020, 07:55 AM
I wish this help you your comparison function malfunctions. You need to group the 'else', or it does the following (I believe): in the first else-case it valuates 1 or (int) $a[0] == (int) $b[0]. The next ? then makes it evaluate that as boolean again (1 == true or (int) $a[0] == (int) $b[0]). I added 2 brackets and this works for me:
code :
function sortByZeroethElement($a, $b)
{
    return (int) $a[0] > (int) $b[0] ? 1 : ((int) $a[0] == (int) $b[0] ? 0 : -1);
}
foreach ($data as $key => &$series)
{
    usort($series, function($a, $b) { return $a[0] - $b[0]; });
}
Unable to sort string array in android, Arrays.sort causes fatal exception

Unable to sort string array in android, Arrays.sort causes fatal exception


By : Vijay Sharma
Date : March 29 2020, 07:55 AM
will be helpful for those in need 08-03 00:45:25.287: E/AndroidRuntime(676): Caused by: java.lang.NullPointerException
Basically you are creating a big array of nulls and then trying to sort it -> NPE.
Sort a two dimensional String array with Arrays.sort based on a chosen column

Sort a two dimensional String array with Arrays.sort based on a chosen column


By : foram
Date : March 29 2020, 07:55 AM
help you fix your problem I have a two dimensional array filled with strings in Java. I want to be able to sort the entire array relative to the column I have chosen to sort by. , Sure, just pass the column index in as a parameter of the comparator.
code :
class ColumnComparator<T extends Comparable<T>> implements Comparator<T[]> {
  private final int column;

  ColumnComparator(int column) { this.column = column; }

  @Override public int compare(T[] a, T[] b) {
    return a[column].compareTo(b[column]);
  }
}
class ColumnComparator implements Comparator<String[]> {
  @Override public int compare(T[] a, T[] b) {
    return a[1].compareTo(b[1]);
  }
}
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