How does this regexp work?

How does this regexp work?

By : Darryl Yust
Date : November 22 2020, 10:31 AM
hope this fix your issue RegExes give me headaches. I have a very simple regex but I don't understand how it works. , How does it work?
code :



# and so on since quantifier * matches any number of character. ? makes the match non greedy

var str = "startBla1end startBla2end startBla3end";
var regex = /start(.*?)(?=end)/gmi;
var match = str.match(regex);
console.log( match ); // [ "startBla" , "startBla2" , "startBla3" ]

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emacs regexp-builder doesn't work in replace-regexp

emacs regexp-builder doesn't work in replace-regexp

By : Charlie R
Date : March 29 2020, 07:55 AM
With these it helps regexp-builder can show the regexp in several syntaxes. By default, it uses the syntax that is appropriate to put in an Emacs Lisp source (read syntax), so the regexp is placed between double quotes and every backslash is doubled. For interactive use, select the string syntax with C-c C-i (reb-change-syntax).
Why won't this JS RegExp work?

Why won't this JS RegExp work?

By : Sylviie Meuger
Date : March 29 2020, 07:55 AM
will help you It's working fine, except for the third one, because that one contains a -. And by the way, _ may be supported as well.
So, a better regular expression would be: /^(http:\/\/www.youtube.com\/v\/)([a-zA-Z0-9-_]*)(\?[^\?]*)$/.
code :
> "http://www.youtube.com/v/baa-dGj2LhQ?fs=1&amp;hl=en_US".replace(/^(http:\/\/www.youtube.com\/v\/)([a-zA-Z0-9-_]*)(\?[^\?]*)$/, '$2');
< "baa-dGj2LhQ"
var addImages = function () {

  // Part 1
  var features = document.getElementById('features'),
  embeds = features.getElementsByTagName('embed'),
  pattern = /^(http:\/\/www.youtube.com\/v\/)([a-zA-Z0-9-_]*)(\?[^\?]*)$/,
  ids = [], i, thumbNav, items, mysrc, ytid, newImg;

  for (i = 0; i < embeds.length; i++) {
    ids[i] = embeds[i].src.replace(pattern, '$2');

Shouldn't this RegExp work?

Shouldn't this RegExp work?

By : Rafa Elías W
Date : March 29 2020, 07:55 AM
like below fixes the issue You would need to escape the slash in regex literals, and the backslash in string literals which you create regexes from:
code :
var patt = /something\/(\w*)\?/g;
// or
var patt = new RegExp("something/(\\w*)\\?", 'g');
regexp + modrewrite just work

regexp + modrewrite just work

By : Julián Castelblanco
Date : March 29 2020, 07:55 AM
it helps some times None of your rules would work because RewriteRule only matches URI without query string. In mod_rewrite you would do something like this:
code :
Options +FollowSymLinks -MultiViews
# Turn mod_rewrite on
RewriteEngine On
RewriteBase /

RewriteCond %{QUERY_STRING} ^search_type=lost_found&ad_type=&location_id=&x=31&y=12$ [NC]
RewriteRule ^(results_lost_found|results_home)\.html$ /lost_found? [NC,R=301,L]
Regexp won't work

Regexp won't work

By : user4760947
Date : March 29 2020, 07:55 AM
this one helps. I want to apply the following regex to a string. It runs fine with Grant Skinners Regexr, it also runs fine on http://www.regexplanet.com/advanced/java/index.html (case-sensitive set) but Java just won't swallow it. It never hit's the while-loop. Here's my code:
code :
final Pattern ptr = Pattern.compile(
    "([a-z]{2,6})\\b", Pattern.CASE_INSENSITIVE);
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