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Android: Emoticon Keyboard unable to get emoticon working on cursor adapter


Android: Emoticon Keyboard unable to get emoticon working on cursor adapter

By : user2954558
Date : November 22 2020, 10:31 AM
Does that help I think there might be some error in saving spanned to database. Save spanned string using
code :
String htmlString = Html.toHtml(spannedText);
Spanned cs = Html.fromHtml(htmlString, imageGetter, null);


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How to make a Emoticon Keyboard

How to make a Emoticon Keyboard


By : Poxer
Date : March 29 2020, 07:55 AM
I wish this help you I am trying to develop a emoticon keyboard for Android. I would like for the user to be able to purchase the app and install the emoticons to use with their keyboard for text and social networking my emoticons are graphics would I have to create a softkeyboard? how can I go about making this app any source codes advice would be appreciated I am new to app development its nothing like web..PLEASE HELP!! ,
I am trying to develop a emoticon keyboard for Android
Implementations of Emoji (Emoticon) View/Keyboard Layouts

Implementations of Emoji (Emoticon) View/Keyboard Layouts


By : Ayman Alsaidi
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I found a very useful Emoticon Keyboard. This keyboard is not using Unicode sequences but rather just local image assets. I am thinking that this type of keyboard can only be useful within this app and not with other apps or Operating Systems.
So instead I am replacing the ImageView containing an asset with a TextView containing a Unicode sequence.
code :
EditText messageInput = (EditText) findViewById(R.id.message_input);
messageInput.getText().append("\ud83d\ude01");
Detecting if a character in a String is an emoticon (using Android)

Detecting if a character in a String is an emoticon (using Android)


By : Tavares Jáder
Date : March 29 2020, 07:55 AM
it helps some times I was in fact able to use the linked iOS code to create the following function. I didn't realize that a String that contains, for example, a single emoticon will have a length of 2. So you can check if a character is in fact a surrogate.
I'm not entirely sure how to handle else if (substring.length > 1) from the iOS code but I think Character.isHighSurrogate(myChar) does the same job in that instance.
code :
private boolean containsIllegalCharacters(String displayName)
{
    final int nameLength = displayName.length();

    for (int i = 0; i < nameLength; i++)
    {
        final char hs = displayName.charAt(i);

        if (0xd800 <= hs && hs <= 0xdbff)
        {
            final char ls = displayName.charAt(i + 1);
            final int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;

            if (0x1d000 <= uc && uc <= 0x1f77f)
            {
                return true;
            }
        }
        else if (Character.isHighSurrogate(hs))
        {
            final char ls = displayName.charAt(i + 1);

            if (ls == 0x20e3)
            {
                return true;
            }
        }
        else
        {
            // non surrogate
            if (0x2100 <= hs && hs <= 0x27ff)
            {
                return true;
            }
            else if (0x2B05 <= hs && hs <= 0x2b07)
            {
                return true;
            }
            else if (0x2934 <= hs && hs <= 0x2935)
            {
                return true;
            }
            else if (0x3297 <= hs && hs <= 0x3299)
            {
                return true;
            }
            else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50)
            {
                return true;
            }
        }
    }

    return false;
}
convert text to emoticon in android

convert text to emoticon in android


By : user2380098
Date : March 29 2020, 07:55 AM
Any of those help Use built in library
https://github.com/ankushsachdeva/emojicon
Adding emoticon to comments but not working

Adding emoticon to comments but not working


By : Mario Acero
Date : March 29 2020, 07:55 AM
will help you You have called your array $smilies when you declare it but are calling it in your foreach loop as $smiles.
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