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Grouping XML children together with XPath in Java


Grouping XML children together with XPath in Java

By : user2954536
Date : November 22 2020, 10:31 AM
this will help You can't use a single XPath 1.0 expression to rearrange nodes into groups.
What you can do is actually select the Flt970 elements, iterate over those, and grab the elements inside them:
code :
XPathExpression expr = xpath.compile("//TOC//SSIFlds/Fld970");
//evaluate expression result on XML document
NodeList nodes = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

for (int i = 0; i < nodes.getLength(); i++) {
    Element node = (Element)nodes.item(i);
    String l = getChildValue(node, "l"), 
           t = getChildValue(node, "t"), 
           p = getChildValue(node, "p");

    // use l, t, and p as needed
}

// defined elsewhere
private static String getChildValue(Element parent, String childName) {
    NodeList nodes = parent.getElementsByTagName(childName);
    return nodes.getLength() > 0 ? nodes.item(0).getTextContent() : "";
}


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Why does my XPath expression in Java return too many children?

Why does my XPath expression in Java return too many children?


By : Deet
Date : March 29 2020, 07:55 AM
will help you I have the following xml file: , so the xpath looks like: /config/a/b/*/text(). And the output for :
code :
for (int i = 0; i < nodes.getLength(); i++) {
        System.out.println(nodes.item(i).getNodeValue());
    }
Java xpath, select most deep children

Java xpath, select most deep children


By : Lijith K P
Date : March 29 2020, 07:55 AM
it helps some times I'm new to Java and XPath syntax. I have complex xml document. What I need is to select all the nodes, that don't have children (I need their values actually). , Ok, this is, what I need
code :
root.selectNodes("//*[not(*)]")
(Java)VTD-XML & Xpath Compering Nodes Children Elements

(Java)VTD-XML & Xpath Compering Nodes Children Elements


By : Anuj
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have two xml files. One is reference(old) file and another one is test(new) file. Based on some rules supplied to me I have to check if something was removed from old model and then added to new one or check if something from old file was removed in new file. , I found the solution to my problem:
code :
public void validateBooleanVTD2(PropertyRule prop, int i) throws XPathParseException, XPathEvalException,
        NavException {
    int n = -1;
    String xPath = prop.getEntitiesObjects().get(i).getxPath(); // eg. /people/man/attribute[not(key)]
    String propertyChecked = prop.getTag(); // eg. mandatory 
    VTDGen parseRef = new VTDGen();
    VTDGen parseTest = new VTDGen();
    parseRef.parseFile(ref, false);
    parseTest.parseFile(test, false);
    VTDNav navigateRef = parseRef.getNav();
    VTDNav navigateTest = parseTest.getNav();
    AutoPilot autopilotRef = new AutoPilot();
    AutoPilot autopilotTest = new AutoPilot();
    autopilotRef.bind(navigateRef);
    autopilotTest.bind(navigateTest);
    autopilotRef.selectXPath(xPath);
    //Instant start = Instant.now();

    while ((n = autopilotRef.evalXPath()) != -1) {
        int nameIndexRef = navigateRef.getAttrVal("name");
        String nameRef = navigateRef.toNormalizedString(nameIndexRef);
        //System.out.println(navigateTest.toString(n + 2));
        //System.out.println(navigateTest.toString(n + 1));
        AutoPilot autopilotRefTestTag = new AutoPilot();
        AutoPilot autopilotTestTestTag = new AutoPilot();
        autopilotRefTestTag.bind(navigateRef);
        autopilotTestTestTag.bind(navigateTest);
        autopilotTestTestTag.selectXPath(xPath + "[@name='" + nameRef + "'][descendant::"+propertyChecked+"]"); // property in Test
        autopilotRefTestTag.selectXPath(xPath + "[@name='" + nameRef + "'][descendant::"+propertyChecked+"]"); // property in Ref
        if(autopilotRefTestTag.evalXPathToBoolean() == true && autopilotTestTestTag.evalXPathToBoolean() == false)
        {
            System.out.println(nameRef/* +":"+navigateRef.toString(n)+":"+propertyChecked + ":Updated:"+prop.getTrue2falseValue()+":Changed From True to False:"+prop.getTrue2falseDesc()*/);
        }
        if(autopilotRefTestTag.evalXPathToBoolean() == false && autopilotTestTestTag.evalXPathToBoolean() == true)
        {
            System.out.println(nameRef/* +":"+navigateRef.toString(n)+":"+propertyChecked + ":Updated:"+prop.getFalse2trueValue()+":Changed From False to True:"+prop.getFalse2trueDesc()*/);
        }

    }


}
XPath Expression For Selecting All Children Nodes Without Decendents Java

XPath Expression For Selecting All Children Nodes Without Decendents Java


By : Ralena Olsen
Date : March 29 2020, 07:55 AM
hop of those help? So I am using XPath in my Java application to parse an xml file. The file format is as follows: , I tried this in xpath tester online and it worked:
code :
RootNode/node()[not(*)]
Java - dom4j XPath for children nodes

Java - dom4j XPath for children nodes


By : Kyle Garcia
Date : March 29 2020, 07:55 AM
I hope this helps you . I am using [dom4j]1 and [XPath]2 in order to traverse an XML.
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