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Interface cannot declare types


Interface cannot declare types

By : user2954512
Date : November 22 2020, 10:31 AM
will help you Just move your class outside of the Interface definition. Also, it is best practice not to nest interfaces (for C#, it is generally best practice to use 1 class/interface per file)
code :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Runtime.Serialization;
using System.ServiceModel;
using System.ServiceModel.Web;
using System.Text;
using System.Data.SqlClient;
using System.Data;

namespace WCFServiceForInsert
{

// REMARQUE : vous pouvez utiliser la commande Renommer du menu Refactoriser pour changer le nom d'interface "IService" à la fois dans le code et le fichier de configuration.
// There is not a reason to keep this IService unless it is necessary for some other piece of your code
[ServiceContract]
public interface IService
{


}

    // NOTE: You can use the "Rename" command on the "Refactor" menu to change the interface name "IService1" in both code and config file together.
    [ServiceContract]
    public interface IService1
    {
        [OperationContract]
        string InsertUserDetails(UserDetails userInfo);

        [OperationContract]
        DataSet SelectUserDetails();
    }


    // Use a data contract as illustrated in the sample below to add composite types to service operations.
    // You must declare this outside of the Interface definition.
    [DataContract]
     public class UserDetails
    {
        int id;
        string title;
        string salary;
        string benefits;
        string keywords;
        string jobType;
        string location;
        string startDate;
        string description;
        string recruitmentAgency;
        string agencyContact;
        string agencyPhone;
        string agencyEmail;
        string jobRef;
        string datePosted;
        string dateExpire;

        [DataMember]
        public int JobID
        {
            get { return id; }
            set { id = value; }
        }

        [DataMember]
        public string Title
        {
            get { return title; }
            set { title = value; }
        }
        [DataMember]
        public string Salary
        {
            get { return salary; }
            set { salary = value; }
        }
        [DataMember]
        public string Benefits
        {
            get { return benefits; }
            set { benefits = value; }
        }
        [DataMember]
        public string Keywords
        {
            get { return keywords; }
            set { keywords = value; }
        }
        [DataMember]
        public string JobType
        {
            get { return jobType; }
            set { jobType = value; }
        }
        [DataMember]
        public string Location
        {
            get { return location; }
            set { location = value; }
        }
        [DataMember]
        public string StartDate
        {
            get { return startDate; }
            set { startDate = value; }
        }
        [DataMember]
        public string Description
        {
            get { return description; }
            set { description = value; }
        }
        [DataMember]
        public string RecruitmentAgency
        {
            get { return recruitmentAgency; }
            set { recruitmentAgency = value; }
        }
        [DataMember]
        public string AgencyContact
        {
            get { return agencyContact; }
            set { agencyContact = value; }
        }
        [DataMember]
        public string AgencyPhone
        {
            get { return agencyPhone; }
            set { agencyPhone = value; }
        }
        [DataMember]
        public string AgencyEmail
        {
            get { return agencyEmail; }
            set { agencyEmail = value; }
        }
        [DataMember]
        public string JobRef
        {
            get { return jobRef; }
            set { jobRef = value; }
        }
        [DataMember]
        public string DatePosted
        {
            get { return datePosted; }
            set { datePosted = value; }
        }
        [DataMember]
        public string DateExpire
        {
            get { return dateExpire; }
            set { dateExpire = value; }
        }
    }


 }


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Is there something like an interface to declare function naming only, without parameters and/or return types?

Is there something like an interface to declare function naming only, without parameters and/or return types?


By : Stanislav Samorukov
Date : March 29 2020, 07:55 AM
it should still fix some issue What you need is a generic type.
code :
Public Interface IFoo(Of T)

    Function GiveMeSomething() As T

End Interface

Public Class Foo
    Implements IFoo(Of Foo)

    Public Function GiveMeANewFoo() As Foo Implements IFoo(Of Foo).GiveMeSomething
        Return New Foo()
    End Function

End Class
Dim oldFoo As New Foo()
Dim newFoo As Foo = oldFoo.GiveMeANewFoo()
Public Interface IFoo

    Function GiveMeSomething() As Object

End Interface

Public Interface IFoo(Of T)
    Inherits IFoo

    Overloads Function GiveMeSomething() As T

End Interface

Public Class Foo
    Implements IFoo(Of Foo)

    Public Function GiveMeANewFoo() As Foo Implements IFoo(Of Foo).GiveMeSomething
        Return New Foo()
    End Function

    Private Function GiveMeANewFooInternal() As Object Implements IFoo.GiveMeSomething
        Return Me.GiveMeANewFoo()
    End Function

End Class
Dim oldFoo As Foo = New Foo()
Dim newFoo As Foo = oldFoo.GiveMeANewFoo() 
'                   IFoo(Of Foo).GiveMeSomething | Foo.GiveMeANewFoo
Dim oldFoo As IFoo(Of Foo) = New Foo()
Dim newFoo As Foo = oldFoo.GiveMeSomething() 
'                   IFoo(Of Foo).GiveMeSomething | Foo.GiveMeANewFoo
Dim oldFoo As IFoo = New Foo()
Dim newFoo As Object = oldFoo.GiveMeSomething() 
'                      IFoo.GiveMeSomething | Foo.GiveMeANewFooInternal
Typescript: Declare function that takes parameter of exact interface type, and not one of its derived types

Typescript: Declare function that takes parameter of exact interface type, and not one of its derived types


By : homesicknomad
Date : March 29 2020, 07:55 AM
like below fixes the issue You cannot achieve this in Typescript, in general, in most languages you cannot make such a constraint. One principle of object oriented programming is that you can pass a derived class where a base class is expected. You can perform a runtime check and if you find members that you don't expect, you can throw an error. But the compiler will not help you achieve this.
Declare an interface where concrete implementation has concrete types

Declare an interface where concrete implementation has concrete types


By : Shawn Gaffney
Date : March 29 2020, 07:55 AM
This might help you , Let's simplify the problem. Suppose we have:
code :
class Animal {}
class Giraffe : Animal {}
interface IFoo 
{
  Animal M(); 
}
class C : IFoo
{
  public Giraffe M() => new Giraffe();
}
class C : IFoo 
{
  Animal IFoo.M() => this.M();
  public Giraffe M() => new Giraffe();
}
interface IBar() 
{
  void N(Giraffe g); 
}
class D : IBar
{
  public void N(Animal g) { ... }
}
interface IBaz 
{
  void P(Animal a);
}
class E : IBaz
{
  public void P(Giraffe g) { } 
}
Adapting a Class to an Interface when it implements all of the interface but doesn't declare the interface

Adapting a Class to an Interface when it implements all of the interface but doesn't declare the interface


By : user1892282
Date : March 29 2020, 07:55 AM
hope this fix your issue Yes, the 3 methods you've done is all you need. A dictionary allegedly relies mostly on the hashcode.
However your cast in Equals(object obj) will go wrong: it will cast a Booh to null. You want to test/cast both FooBar and just plain T.
code :
    bool Equals(FooBar<T> other)
    {
        return EqualityComparer<T>.Default.Equals(Value, other.Value);
    }

    public override bool Equals(object obj)
    {
        if (ReferenceEquals(null, obj)) return false;
        if (ReferenceEquals(this, obj)) return true;
        if (obj is T) return Value.Equals(obj);
        if (obj.GetType() != this.GetType()) return false;
        return Equals((FooBar<T>) obj);
    }

    public override int GetHashCode()
    {
        return EqualityComparer<T>.Default.GetHashCode(Value);
    }
    [Fact]
    public void CanUseInDict()
    {
        var foobar= new Booh();
        IFooBar[] foobars= new IFooBar[]{ foobar.AsIFooBar() };
        Dictionary<IFooBar,string> ifoobars= new Dictionary<IFooBar, string>()
        {
            { foobar.AsIFooBar(), foobar.GetType().Name}
        };

        Assert.Equal( foobar.GetHashCode(),  new FooBar<Booh>( foobar ).GetHashCode());
        Assert.True( foobar.AsIFooBar().Equals( new FooBar<Booh>( foobar ) )  , "Equals FooBar<Booh>");
        Assert.True( ifoobars.ContainsKey( new FooBar<Booh>(foobar) ), "ContainsKey");            

        ifoobars.Remove(foobar.AsIFooBar());
        Assert.Empty(ifoobars);
    }
static class BoohFooBarExt
{
    public static IFooBar AsIFooBar<T>(this T value ) where T:IFoo, IBar => new FooBar<T>(value);
}
[Nested interface/type]: How to declare function return types inside a class in Typescript?

[Nested interface/type]: How to declare function return types inside a class in Typescript?


By : CWE
Date : March 29 2020, 07:55 AM
I wish this help you As mentioned in the comments, this isn't currently supported. There is an existing suggestion in GitHub to support allowing a class to also act as a namespace for type declarations. If you care about this feature you might want to go to the GitHub issue and give it a and/or describe your use case if it's especially compelling.
The current workaround is to use declaration merging like this:
code :
// separate namespace 
// not close to your method either 
namespace Foo {
  // must export the type in question 
  export type ReturnObject = {
    isInReferenceList: boolean,
    referenceLabels: string[]
  };
}

class Foo {
  // must refer to the type as fully qualified by namespace 
  getReferenceInfo(word: string): Foo.ReturnObject {
    return null!;
  }
}
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