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Regular expression replace all occurrences of any word beginning with a certain substring


Regular expression replace all occurrences of any word beginning with a certain substring

By : jessamyn west
Date : November 22 2020, 10:31 AM
Any of those help Working with Windows PowerShell, I am trying to replace all occurrences of a certain word pattern in a big string, by appending a suffix. , Something like
code :
$string -replace "((?:ab_abcde|ab_vwxyz)\w*)", '$1_XXX'


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Regular Expression to replace substring occurrences when not surrounded by square brackets

Regular Expression to replace substring occurrences when not surrounded by square brackets


By : user3050609
Date : March 29 2020, 07:55 AM
Any of those help Using a perl style regex with a negative look-behind (? code :
R> gsub("(?<!\\[)\\!(?!\\])", "!\n", x, perl=TRUE)
[1] "this!\n"                   "is!\n"                    
[3] "not my name[!]!\n"         "Understrand[!] Mate!\n"   
[5] "Because!\nI[!] said so!\n"
R> gsub("(?<!\\[)\\!|\\!(?!\\])", "!\n", c("aa[!bb", "aa!]bb"), perl=TRUE)
[1] "aa[!\nbb" "aa!\n]bb"
Does regular expression allow you to replace the ending and beginning of a word?

Does regular expression allow you to replace the ending and beginning of a word?


By : Hugo Rodríguez
Date : March 29 2020, 07:55 AM
this will help I'm having one heck of a time figuring out regular expression in the context of the grunt-string-replace plugin. , You can use a regex like this:
code :
!([\w-]+)\{\}
.\1;
Python: Replace all substring occurrences with regular expressions

Python: Replace all substring occurrences with regular expressions


By : Eduard Cealenco
Date : March 29 2020, 07:55 AM
I wish this help you You can search for all of the strings at once, so that the fact that one is a substring of another doesn't matter:
code :
re.sub(r"(house|the house)", r"**\1**", mystring)
Replace all occurrences matching regular expression in the first word of a line

Replace all occurrences matching regular expression in the first word of a line


By : Lindajohnson80
Date : March 29 2020, 07:55 AM
it should still fix some issue You may achieve that with re using a regex to match the first word up to the first whitespace after the first streak of non-whitespace chars and a lambda expression as the replacement argument:
code :
re.sub(r"^\s*\S+", lambda x: x.group().replace('.', r'\.'), s)
import regex
s = 'DXa0.Xa1.a2 p1 p2 deviceName  a=157.585p b=54.46u $x=106.124 $y=107.996 $a=0'
rx = r'\G[^\s.]*\K\.'
print(regex.sub(rx, r'\\.', s))
regex.sub(r'\G([^\s.]*)\.', r'\1\\.', s)
regular expression sub method does not replace all occurrences in python regular expression

regular expression sub method does not replace all occurrences in python regular expression


By : Ken Craft
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You may use lookarounds in your regex since you have overlapping matches:
code :
(?<= )&&(?= )
>>> string =" && && 7978888 && 896"
>>> tmp = re.sub(r"(?<= )&&(?= )", "and", string)
>>> tmp
' and and 7978888 and 896'
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