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How do I offer JSON as a url with parameters?


How do I offer JSON as a url with parameters?

By : user2954396
Date : November 22 2020, 01:01 AM
around this issue You have a lot of options as far as server-side technology, but in the end, you need to accept the parameters, select your data and return content that is application/json. Since you have a SQL Server back-end, you might look at Microsoft's Web API as the technology to expose your data.
code :


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Database structure for application, offer, and accepted offer

Database structure for application, offer, and accepted offer


By : arkheem
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I would place a column on the applications table named "accepted_offer_id" that references the offer that has been accepted.
This guarantees that the number of accepted offers is either 0 or 1, and avoids having to implement a slightly tricky bit of logic to ensure that only one offer per application can have an "is_accepted" value of true.
How to offer lists of valid values for parameters in a RESTful API?

How to offer lists of valid values for parameters in a RESTful API?


By : Yatie Mekktiey
Date : March 29 2020, 07:55 AM
I wish did fix the issue.
"a good REST API is like an ugly website" -- Rickard Öberg
Why Does Intellisense Offer Json for a Constant?

Why Does Intellisense Offer Json for a Constant?


By : Zhi Hao
Date : March 29 2020, 07:55 AM
I wish this help you I declared a constant, assigned to a fetch. Now, intellisense offers json for that constant. , A few things; first:
Does Json.NET offer an instance API?

Does Json.NET offer an instance API?


By : user3216230
Date : March 29 2020, 07:55 AM
around this issue Yes, of course. JsonConvert is just a facade to make it easier to do common tasks with JsonSerializer. You can create different instances of JsonSerializer and use them independently if you want. All of the settings in the JsonSerializerSettings class are also on the JsonSerializer itself. Have a look at the source code if you want to see how JsonConvert wraps JsonSerializer and transfers settings to it.
Note that the JsonSerializer class deals with JsonReader and JsonWriter; it does not have the same easy-to-use methods to work directly with objects and strings that JsonConvert has. However, it is very easy to make some simple extension methods to do the same thing if that is what you need:
code :
public static class JsonSerializerExtensions
{
    public static string SerializeObject(this JsonSerializer serializer, object obj)
    {
        using (StringWriter sw = new StringWriter())
        using (JsonTextWriter writer = new JsonTextWriter(sw))
        {
            serializer.Serialize(writer, obj);
            return sw.ToString();
        }
    }

    public static T DeserializeObject<T>(this JsonSerializer serializer, string json)
    {
        using (StringReader sr = new StringReader(json))
        using (JsonTextReader reader = new JsonTextReader(sr))
        {
            return serializer.Deserialize<T>(reader);
        }
    }
}
JsonSerializer ser = new JsonSerializer { Formatting = Formatting.Indented };

Foo foo = new Foo();
string json = ser.SerializeObject(foo);

foo = ser.DeserializeObject<Foo>(json);
Why does typedef not offer protection in function parameters?

Why does typedef not offer protection in function parameters?


By : Shilpa
Date : March 29 2020, 07:55 AM
this will help typedefs are just an alias to a type, it does not make a new type. If both typedefs alias the same type then you can interchange them.
It looks like you can use a strong typedef or you could wrap the type in a wrapper class and use the wrapper class as the function parameter.
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