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Remove spaces from char-array by using a function with a pointer argument


Remove spaces from char-array by using a function with a pointer argument

By : Tom
Date : November 22 2020, 01:01 AM
I think the issue was by ths following , The call to removeSpaces has no affect because you are creating a temporary buffer in the function and copying the string into that while applying the transformation. You can fix this by removing the temporary buffer and just modifying the string in place.
code :
void removeSpaces(char* s)
{
    char* cpy = s;  // an alias to iterate through s without moving s
    char* temp = s;

    while (*cpy)
    {
        if (*cpy != ' ')
            *temp++ = *cpy;
        cpy++;
    }
    *temp = 0;

    cout << s << endl; // This prints out the desired result: abbcccd
}


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Function to remove spaces from string/char array in C

Function to remove spaces from string/char array in C


By : Nidhi Chowdhry
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further After removing the white spaces from the input you have not terminated it with nul-terminator (\0) because the new length is less than or equal to the original string.
Just nul-terminate it at the of end your for loop:
code :
char* deblank(char* input)                                         
{
    int i,j;
    char *output=input;
    for (i = 0, j = 0; i<strlen(input); i++,j++)          
    {
        if (input[i]!=' ')                           
            output[j]=input[i];                     
        else
            j--;                                     
    }
    output[j]=0;
    return output;
}
How to pass a float array to the function that has unsigned char pointer as an argument?

How to pass a float array to the function that has unsigned char pointer as an argument?


By : modifiedcontent
Date : March 29 2020, 07:55 AM
I wish this helpful for you In the first snippet, the float data starts at byte 2 of the char array. In the second snippet, it starts at byte 0.
It looks like the missing two bytes are the key to why one works and the other doesn't.
Const char array with template argument size vs. char pointer

Const char array with template argument size vs. char pointer


By : user2506668
Date : March 29 2020, 07:55 AM
hop of those help? The intent of passing any raw pointer to a function is the caller has some idea of:
What it points to. How many it points to.
code :
void f(const char *s)
{
    // how many char does s refer to?
}
void f(const char *s, std::size_t N)
{
    // Now the caller is telling us there are N chars at s
}
template<std::size_t N>
void f(const char(&ar)[N])
{
    // we know the caller is passing a const-reference to a
    // char array declared of size N. The value N can be used
    // in this function.
}
// length specified implementation
void f(const char *s, std::size_t N)
{
    // caller passed N
}

// fixed buffer template wrapper
template<std::size_t N>
void f(const char(&ar)[N])
{
    f(ar,N); // invokes length-specified implementation from above.
}
int main()
{
    char buff[3];

    f(buff,3);
    f(buff);

}
int main()
{
    char buff[3];
    const char *ptr = buff;
    f(ptr); // ERROR: no matching function f(const char *)
}
Passing a pointer to a char array as an argument to a function - C

Passing a pointer to a char array as an argument to a function - C


By : user3048768
Date : March 29 2020, 07:55 AM
it should still fix some issue Yes, in passing arguments to a function, char *args[] is equivalent to char **args.
In the first argument, char inputBuffer[], the function actually receives not the whole char array but only a pointer variable holding the address of its first element.
Why doesn't gets() take a char pointer argument if it can take a char array?

Why doesn't gets() take a char pointer argument if it can take a char array?


By : Michael Reid
Date : March 29 2020, 07:55 AM
To fix this issue The gets function expects s to point to a character array that can accept a string. But in this case, s is uninitialized. So gets tries to dereference an uninitialized pointer. This invokes undefined behavior.
If you were to set s to point to a preexisting array or if you used malloc to allocate space, then you can write to it successfully.
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