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Input numbers until -1 is inputed


Input numbers until -1 is inputed

By : user2954229
Date : November 22 2020, 01:01 AM
I think the issue was by ths following , The problem is that after a complete line has been entered n is never reset to a default value and still contains -1. On the next iteration this causes the inner while loop to be skipped and temp.front() to be called on an empty vector, which is undefined behavior. The following updates should get you back on track.
code :
while(true)
{
    vector<int> temp;
    while(n!=-1)
    {
        cin>>n;
        temp.push_back(n);
    }
    n = 0; // RESET n to a default value

    // Add additional check just to be sure.
    if(temp.size() == 0 || temp.front()== -1)
      break;

    waiters.push_back(temp);        
}


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How to display the numbers inputed in a text field?

How to display the numbers inputed in a text field?


By : user45547
Date : March 29 2020, 07:55 AM
should help you out I am creating a form with one field to input numbers . How can I show the value of the numbers in text format in the below text field ? , here you are
code :
function readable_number(num){
    var bits_a = ["thousand", "million", "billion", "trillion", "zillion"];
    var bits_b = ["ten", "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety"];
    var bits_c = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"];

    if (num==0){return 'zero';}

    var result = (num<0)?'minus ':'';

    num = Math.abs(num);
    for(var i=bits_a.lenght; i>0; i--){
        var p = pow(1000, i);
        if (num > p){
            var b = Math.floor(num/p);
            num -= p * b;
            result += readable_number(b) + ' ' + bits_a[i-1];
            result += ((num)?', ':'');
        }
    }
    if (num > 100){
        var b = Math.floor(num/100);
        num -= 100 * b;
        result += readable_number(b) + ' hundred' + ((num)?' and ':' ');
    }
    if (num >= 20){
        var b = Math.floor(num/10);
        num -= 10 * b;
        result += bits_b[b-1] + ' ';
    }
    if (num){
        result += bits_c[num-1];
    }
    return result;
}

alert(readable_number(1234));
calculate inputed numbers from textboxes

calculate inputed numbers from textboxes


By : Warattaya Hooya
Date : March 29 2020, 07:55 AM
like below fixes the issue My mission to my program is when a record filtered in the textboxes if i change the numbers it will automatically change the total and calculate in the (total)textbox...can anyone help me whats wrong with my code? I porposely dont loop the textboxes because i have plans on it. , use this on onchange event
code :
 function optTotal() {
        var a1 = document.forms[0].optA;
        var b1 = document.forms[0].optB;
        var c1 = document.forms[0].optC;
        var d1 = document.forms[0].optD;
        if (a1.value && a1.value != "")
            a1 = parseFloat(a1.value);
        else
            a1 = 0;

        if (b1.value && b1.value != "")
            b1 = parseFloat(b1.value);
        else
            b1 = 0;

        if (c1.value && c1.value != "")
            c1 = parseFloat(c1.value);
        else
            c1 = 0;

        if (d1.value && d1.value != "")
            d1 = parseFloat(d1.value);
        else
            d1 = 0;


        var total = a1 + b1 + c1+d1;
        document.forms[0].total.value = total;
      }
How to add inputed numbers in string.(Python)

How to add inputed numbers in string.(Python)


By : Sumathi Kotthuri
Date : March 29 2020, 07:55 AM
With these it helps You're close, you just need to split the string on spaces. Splitting will produce the list of strings ['-5', '5', '3', '5']. Then you can do the rest of the map and sum as you intended.
code :
>>> s = '-5 5 3 5'
>>> sum(map(int, s.split()))
8
using array print numbers inputed by user ignore duplicate numbers

using array print numbers inputed by user ignore duplicate numbers


By : dieler
Date : March 29 2020, 07:55 AM
Hope this helps What about a write a function to check whether we are going to print the number or not? So that you don't need to sort the inputted array. Moreover, no builtin methods are used.
code :
import static java.lang.System.*;
import java.util.*;

public class Uni {
    public static boolean isContain(int[] src, int end, int value) {
        int start;
        for (start = 0; start < end; start++) {
            if (src[start] == value) {
                return true;
            }
        }
        return false;
    }
    public static void main(String[] args) {
        Scanner sc = new Scanner(in);
        int[] a = new int[5];
        for (int i = 0; i < a.length; i++) {
            out.println("Please type a number");
            a[i] = sc.nextInt();
        }

        for (int i = 0; i < a.length; i++) {
            if (i == 0) {
                out.print(a[i] + " ");
            } else {
                if (!isContain(a, i, a[i])) {
                    out.print(a[i] + " ");
                }
            }
        }
    }
}
how do I find the max of inputed numbers

how do I find the max of inputed numbers


By : Katie McAuliffe
Date : March 29 2020, 07:55 AM
wish of those help You can either put them all into a list and then run max() on the list, or (if you don't need the list for anything else) simply maintain your own maximum with something like:
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