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Can I connect all nodes in one subgraph to all nodes in another with a single DOT statement?


Can I connect all nodes in one subgraph to all nodes in another with a single DOT statement?

By : John Peterson
Date : November 21 2020, 07:31 AM
it helps some times First the answer: No, there is no syntax for such a thing as connecting all nodes of a subgraph to all nodes of an other subgraph by only naming the subgraphs.
You will have to list explicitely all nodes to connect with each other.
code :


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subgraph of an acyclic graph covering some selected nodes but other nodes not on the path

subgraph of an acyclic graph covering some selected nodes but other nodes not on the path


By : JakenVeina
Date : March 29 2020, 07:55 AM
wish helps you I feel like I misunderstood the problem but let's give it a try.
First we have to assume/check that your graph is a connected component http://en.wikipedia.org/wiki/Connected_component_(graph_theory) and then you can start :
code :
solution = sV
foreach n1 in sv
    foreach n2 in sv, n2!=n1
        path = findPath(G,n1,n2)  
        // this should return at least one path because of connectivity
        // and no more than one
        for each n3 in path
            solution += n3
R and igraph: subgraph nodes based on attributes of other nodes that are incident on edge

R and igraph: subgraph nodes based on attributes of other nodes that are incident on edge


By : Avdesh
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have collaboration data of inventors on patents. Each inventor is a node, each edge represents a patent on which two inventors have collaborated. Some patents have >2 inventors, so some patents are represented with multiple edges. , How about this
code :
#final all patent names
patents <- unique(edge.attributes(gg)$patent)

#check if criteria are met for patent
okpatents <- sapply(patents, function(p){
    cities <- V(gg)[inc(E(gg)[patent==p])]$city
    nc <- sum(cities=="BOISE")
    return(nc>0 & nc < length(cities))
})

#extract subgraph
gs <- subgraph.edges(gg, E(gg)[patent %in% patents[okpatents]])

#verify
plot(gs, edge.label=E(gs)$patent)
Getting subgraph of nodes between two nodes?

Getting subgraph of nodes between two nodes?


By : Coolroe
Date : March 29 2020, 07:55 AM
like below fixes the issue My answer is very similar to back2basics, but more directly finds the nodes between the two. If there is a path from source to target, that path will be found by nx.all_simple_paths(G, source=source, target=target) which returns a generator for the paths.
code :
import networkx as nx

G = nx.Graph()
G.add_edges_from([(1, 2), (2, 3), (3, 4), (3, 5), (4, 6), (5, 6), (3, 7), (7, 6), (6, 8), (8, 9)])

paths_between_generator = nx.all_simple_paths(G,source=3,target=6)
nodes_between_set = {node for path in paths_between_generator for node in path}
SG = G.subgraph(nodes_between_set)
nodes_between_set = set()
for path in paths_beween_generator:
    for node in path:
        nodes_between_set.add(node)
r igraph - Identify ties of nodes to a subgraph regardless of affiliation to said subgraph

r igraph - Identify ties of nodes to a subgraph regardless of affiliation to said subgraph


By : Isatron3000
Date : October 14 2020, 09:38 AM
Any of those help How to count the ties of a node to a subgraph of the same graph? In a school context, how to count student G's friends in a specific class, regardless of her belonging there? , You can get the neighbours first, and use them to subset schoolsub:
code :
nbs <- neighbors(schoolgraph, "G")$name
V(schoolsub)$name[V(schoolsub)$name %in% nbs]
#[1] "A" "C"
Nodes or set of nodes connected to a subgraph networkx

Nodes or set of nodes connected to a subgraph networkx


By : Adam Darwin
Date : March 29 2020, 07:55 AM
this one helps. If B is strongly connected, then if you choose any node u in B, then if some node x in A has a path to some node b in B, then there is a path from x to u (there is a path from b to u because B is strongly connected and then the x to b to u path exists). So having a path to any node in B is the same thing as having a path to one specific node in B. Let X be the set of nodes with a path to u. This is the set you want.
If you do X = nx.ancestors(A, u) then X is the set of nodes with a path to u. If you want the subgraph itself, then do G = A.subgraph(X), but if you just want the set of nodes, then it's X.
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