Generate random string for member of struct

Generate random string for member of struct

By : Piers Lafond
Date : November 21 2020, 07:31 AM
To fix this issue I would like to know how I can generate a random string for a member of a struct and assign this value to the member of the struct. , This will generate random string of lowercase characters
code :
generate_random_string(char *string, size_t length)
    size_t i;
    for (i = 0 ; i < length - 1 ; i++)
        string[i] = rand() % ('z' - 'a') + 'a';
    string[length - 1] = '\0';
generate_random_string(s.name, sizeof(s.name));

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generate random numbers (no member generate exist error)

generate random numbers (no member generate exist error)

By : Siddartha
Date : March 29 2020, 07:55 AM
This might help you The engine std::mt19937 requires a seed in its constructor. You are passing it an std::random_device. It looks like you intended to do something like
code :
Engine::Engine() : m_generator(m_seed()), m_distribution(0, 36) {}
    std::random_device m_seed;
    std::mt19937 m_generator;
    std::uniform_int_distribution<int> m_distribution;
Engine::Engine() : m_generator(std::random_device()()), 
                   m_distribution(0, 36) {}
C: Function to generate random string and add it to struct

C: Function to generate random string and add it to struct

By : Dobiems
Date : March 29 2020, 07:55 AM
help you fix your problem You're missing the call to GenerateCode on main, that's the reason the print output is gibberish.
However another issue is that on the GenerateCode function, the parameter is by value and the function won't modify the original struct on main. In C, all and every parameters are by value. You should pass a pointer to the struct:
code :
void GenerateCode(object_t* object) {
    for (int i = 0; i < 2; i++) {
        object->objectCode[i] = RandomLetter();

    for (int i = 2; i < 6; i++) {
        object->objectCode[i] = '0' + RandomDigit();

int main() {

    // ...
    object_t object1;

Generate random number for member in struct

Generate random number for member in struct

By : user2953906
Date : November 21 2020, 07:31 AM
seems to work fine Move srand(time(NULL)); to main().
If you call it in a very short interval the random seed is always the same and that's why you get the same value.
Generate random numbers for member of struct

Generate random numbers for member of struct

By : Sanny
Date : March 29 2020, 07:55 AM
Does that help The following snippet of code solves your problem basing on your comment below. You haven't completely understood how to use structure perhaps. Note that to use member of a structure you must use the . symbol
code :
struct BigInt {
    int *A;

struct BigInt bigIntVar = {

int len;
scanf("%i", &len);

bigIntVar.A = (int*)malloc(len * sizeof(int));

int i = 0;

while (i != len) {
    int r = rand() % 10;
    bigIntVar.A[i] = r + 1;

    printf("\nr:%i\n", r);
    printf("A[i]:%d", bigIntVar.A[i]);
How to call member of a struct using string declaration as representation of the actual member?

How to call member of a struct using string declaration as representation of the actual member?

By : user2994627
Date : March 29 2020, 07:55 AM
I wish did fix the issue. My goal is to call a member of a struct without using the actual member. It sounds confusing but here's my sample code for further explanation: , Like this, basically:
code :
if (!strcmp(input, "name"))
    strcpy(r.name, test1);
    printf("Invalid field!\n");
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