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Python string,re.match,loop


Python string,re.match,loop

By : user2953990
Date : November 21 2020, 07:31 AM
This might help you OK guys I got like 4 example: I love #hacker, I just scored 27 points in the Picking Cards challenge on #Hacker, I just signed up for summer cup @hacker, interesting talk by hari, co-founder of hacker, , you can use re.findall:
code :
my_string = """I love #hacker, I just scored 27 points in the Picking Cards challenge on #Hacker, I just signed up for summer cup @hacker, interesting talk by hari, co-founder of hacker,"""
>>> import re
>>> len(re.findall("hacker",my_string.lower()))
4
>>> len(re.findall("hacker",my_string,re.IGNORECASE))
4


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Ruby Regexp#match to match start of string with given position (Python re-like)

Ruby Regexp#match to match start of string with given position (Python re-like)


By : joro22
Date : March 29 2020, 07:55 AM
wish helps you I'm looking for a way to match strings from first symbol, but considering the offset I give to match method. , How about using a string slice?
code :
/^qwe/.match(test_string[def_pos..-1])
Match String But Don't Match Specific Pattern If It's There In Python

Match String But Don't Match Specific Pattern If It's There In Python


By : Avinash Kushawaha
Date : March 29 2020, 07:55 AM
Hope this helps I'm trying to match a string all the way to the end, but if there is another string separated by a space, then I just want to match the first string and not this extra pattern. This extra patter always starts with: , It seems, you could use
code :
^[A-Z]+\s+(\S+)
import re

string = """
M /trunk
M /trunk/src/chip/GCC/ARMCMx/STM32F4xx/vectors.c
A /trunk/src/hal/include/spdif.h (from /branches/spdif_446/src/hal/include/spdif.h:1078)
M /trunk/src/hal/platforms/STM32/SAI/sai_lld.h
A /trunk/src/hal/platforms/STM32/SPDIF (from /branches/spdif_446/src/hal/platforms/STM32/SPDIF:1078)
A /trunk/src/hal/src/spdif.c (from /branches/spdif_446/src/hal/src/spdif.c:1078)
"""

rx = re.compile(r'^[A-Z]+\s+(\S+)', re.MULTILINE)
files = rx.findall(string)
print(files)

# ['/trunk', '/trunk/src/chip/GCC/ARMCMx/STM32F4xx/vectors.c', 
#  '/trunk/src/hal/include/spdif.h', '/trunk/src/hal/platforms/STM32/SAI/sai_lld.h', 
#  '/trunk/src/hal/platforms/STM32/SPDIF', '/trunk/src/hal/src/spdif.c']
Python match string in loop

Python match string in loop


By : Delana Allo
Date : March 29 2020, 07:55 AM
may help you . , See below with some few inline comments
code :
apdb = {'AP Database': [{'AP Type': '110H',
              'Name': 'varagu',
              'Public IP': '100.20.300.400',
              'Wired MAC Address': 'aa:bb:cc:dd:ee:11'},
             {'AP Type': '110H',
              'Name': 'thinai',
              'Public IP': '100.20.300.500',
              'Wired MAC Address': 'aa:bb:cc:dd:ee:22'},
             {'AP Type': '110H',
              'Name': 'Ragi',
              'Public IP': '100.20.300.600',
              'Wired MAC Address': 'aa:bb:cc:dd:ee:33'}]}


ap_database = apdb.get('AP Database')

# no need to do this since ap_database is already a list, so we can iterate over it.
# apall = ap_database[0], ap_database[1], ap_database[2]

# ip_list does not change, so we can define it once outside the loop
ip_list = ['100.20.300.400', '100.20.300.500', '100.20.300.700']

# let us add two more variables to hold the fail and success list
success_list = []
fail_list = []

for ap in ap_database:

    # ap is a dict, so use ap.get('key') or ap['key'] instead of ap.__getitem__('key')
    # note that ap.get('key') returns None if key does not exist, while ap['key'] throws an error.
    public = ap.get('Public IP')
    name = ap.get('Name')

    # check whether public is in ip_list and print appropriate message
    if public in ip_list:
        print public, name, 'Success'
        success_list.append(ap)
    else:
        print public, name, 'Fail'
        fail_list.append(ap) 
Iterate through a python 3 list of string and match every item against the others and return the the largest match

Iterate through a python 3 list of string and match every item against the others and return the the largest match


By : Jill Wegman Decaro
Date : March 29 2020, 07:55 AM
I wish this help you I think what you're looking for is whether each string is a substring of another string in the list?
If the list is pretty short, like this one, we can do that with a stupid quadratic search:
code :
corrected_list = []
for person in person_list:
    matches = (other for other in person_list if person in other)
    longest = max(matches, key=len)
    corrected_list.append(longest)
Is there a way to have python start a the match statement when a string is found so that loop doesn't start from the beg

Is there a way to have python start a the match statement when a string is found so that loop doesn't start from the beg


By : user3092059
Date : March 29 2020, 07:55 AM
I wish this helpful for you File includes: , Put it in a function and return:
code :
def getCarColor(car, data):

    car_found = False

    for line in data:
        if car in line:
            car_found = True
        if 'color' in line and car_found:
            return get_color(line)

    return None

print(getCarColor("Hyundai", data))

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